Answer:
Step-by-step explanation:
If you have an odd number of consecutive numbers, the middle number should be x. So 7 of them would be written as
(x - 3)+(x - 2) + (x - 1) + x + (x + 1) + (x + 2) + (x+3)
That way all you are left with is 7x because the integers cancel.
That is not your question
You question is
Sum = m+(m + 1) + (m + 2) + (m + 3) + (m + 4) + (m + 5) + (m + 6)
It's the first oneeeeeeeeeeeeeee
Answer:
13x+16
Step-by-step explanation:
3x+7+8x+2x+4+5
13x+7+4+5
13x+16
.hello :
an equation of the circle <span>Center at the w(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : r = 1
</span><span>The points (-18,15) and (-20,15) lie on a circle with a radius of 1:
</span>(-18-a)²+(15-b)² = 1 ....(1)
(-20-a)² +(15-b)² = 1 ....(2)
solve this system :
(1) -(2) : (-18-a)² - (-20-a)² =0
(-18-a)² =(-20-a)² =0
( -18-a = -20-a) or (-18-a = - (-20-a))
1 ) ( -18-a = -20-a) no solution confused : -18=-20
2 ) -18-a =20+a
-2a =38
a = -19
subst in (1) :(-18+19)²+(15-b)² =1
(15-b)² = 0.... 15-b = 0 .... b = 15
the center is :w(-19,15)
Given:
To get rid of the fraction, we can multiply both sides by the denominator, which is 3. This will cancel the fraction:
We are left with:
