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Charra [1.4K]
3 years ago
9

The points (-18,15) and (-20,15) lie on a circle with a radius of 1. Find the coordinates of the center of the circle.

Mathematics
1 answer:
FromTheMoon [43]3 years ago
6 0
.hello :
an equation of the circle <span>Center at the w(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : r = 1
</span><span>The points (-18,15) and (-20,15) lie on a circle with a radius of 1:
</span>(-18-a)²+(15-b)² = 1 ....(1)
(-20-a)² +(15-b)² = 1 ....(2)
solve this system :
(1) -(2) : (-18-a)² - (-20-a)² =0
(-18-a)² =(-20-a)² =0
( -18-a = -20-a) or (-18-a = - (-20-a))
1 )  ( -18-a = -20-a) no solution confused : -18=-20
2 ) -18-a =20+a
      -2a =38
      a = -19 
subst in (1) :(-18+19)²+(15-b)² =1
(15-b)² = 0.... 15-b = 0     .... b = 15
the center is :w(-19,15)
  
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Step-by-step explanation:

The formula for half-life is given as,

R/R' = 2ᵃ/ᵇ...................... Equation 1

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Given: R = 1 kg, R' = 0.0156 kg, a = 90 hours

Substitute into equation 1 and solve for b

1/(0.0156) = 2⁹⁰/ᵇ

Taking the log of both side

log[1/(0.0156)] = log(2⁹⁰/ᵇ)

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90/b = log[1/(0.0156)]/log2

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