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3 years ago

5

while assembling soldier in a square from having 64 soldiers in each row,the officer find 219 soldiers are extra then, to aarang

e all in a square,how many minimum soldiers should be added?

1 answer:

Andreas93 [3]3 years ago

7 0

Answer:

nsx ndsmx sc dmf

Step-by-step explanation:

cbvhdbmx

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Help plz<br>6(2x - 11) + 15 = 3x + 12

Ket [755]

Answer:

x = 7

Step-by-step explanation:

Lets do the brackets first,

6 × 2x = 12

6 × -11 = -66

------

Calculate the x constant:

12x - 3x = 9x

-------

Then the ones with no x:

-66 + 15 = -51

51 + 12 = 63

-------

Lastly, divide

63 ÷ 9 = 7

-------

Have a good day :)

3 0

2 years ago

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All 3,000 seats in a theater are being replaced. So far, 5 sections 136 seats and a sixth section containing 348 seats have been

Ostrovityanka [42]

1,124 seats still need to be replaced.

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3 years ago

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How much is 3/4 of 120? And how much is 3/8 of 160?

RoseWind [281]

3/4 of 120
=3/4*120
=360/4
=90

3/8 of 160
=3/8*160
=480/8
=60

4 0

3 years ago

Read 2 more answers

In Exercises 5-7, find all the exact t-values for which the given statement is true,

bearhunter [10]

Answer: See Below

<u>Step-by-step explanation:</u>

NOTE: You need the Unit Circle to answer these (attached)

5) cos (t) = 1

Where on the Unit Circle does cos = 1?

Answer: at 0π (0°) and all rotations of 2π (360°)

In radians: t = 0π + 2πn

In degrees: t = 0° + 360n

******************************************************************************

$6)\quad sin (t) = \dfrac{1}{2}$

Where on the Unit Circle does $sin = \dfrac{1}{2}$

<em>Hint: sin is only positive in Quadrants I and II</em>

$\text{Answer: at}\ \dfrac{\pi}{6}\ (30^o)\ \text{and at}\ \dfrac{5\pi}{6}\ (150^o)\ \text{and all rotations of}\ 2\pi \ (360^o)$

$\text{In radians:}\ t = \dfrac{\pi}{6} + 2\pi n \quad \text{and}\quad \dfrac{5\pi}{6} + 2\pi n$

In degrees: t = 30° + 360n and 150° + 360n

******************************************************************************

$7)\quad tan (t) = -\sqrt3$

Where on the Unit Circle does $\dfrac{sin}{cos} = \dfrac{-\sqrt3}{1}\ or\ \dfrac{\sqrt3}{-1}\quad \rightarrow \quad (1,-\sqrt3)\ or\ (-1, \sqrt3)$

<em>Hint: sin and cos are only opposite signs in Quadrants II and IV</em>

$\text{Answer: at}\ \dfrac{2\pi}{3}\ (120^o)\ \text{and at}\ \dfrac{5\pi}{3}\ (300^o)\ \text{and all rotations of}\ 2\pi \ (360^o)$

$\text{In radians:}\ t = \dfrac{2\pi}{3} + 2\pi n \quad \text{and}\quad \dfrac{5\pi}{3} + 2\pi n$

In degrees: t = 120° + 360n and 300° + 360n

4 0

2 years ago

Need help with this problem

Zanzabum

Answer:

C. Priya needs to charge at least $21 per bracelet.

Step-by-step explanation:

$117b - 505 \ge 1952$

Add 505 to both sides.

$117b \ge 2457$

Divide both sides by 117.

$b \ge 21$

Answer: C. Priya needs to charge at least $21 per bracelet.

7 0

3 years ago