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rewona [7]
3 years ago
5

while assembling soldier in a square from having 64 soldiers in each row,the officer find 219 soldiers are extra then, to aarang

e all in a square,how many minimum soldiers should be added?​
Mathematics
1 answer:
Andreas93 [3]3 years ago
7 0

Answer:

nsx ndsmx sc dmf

Step-by-step explanation:

cbvhdbmx

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Help plz<br>6(2x - 11) + 15 = 3x + 12​
Ket [755]

Answer:

x = 7

Step-by-step explanation:

Lets do the brackets first,

6 × 2x = 12

6 × -11 = -66

------

Calculate the x constant:

12x - 3x = 9x

-------

Then the ones with no x:

-66 + 15 = -51

51 + 12 = 63

-------

Lastly, divide

63 ÷ 9 = 7

-------

Have a good day :)

3 0
2 years ago
Read 2 more answers
All 3,000 seats in a theater are being replaced. So far, 5 sections 136 seats and a sixth section containing 348 seats have been
Ostrovityanka [42]
1,124 seats still need to be replaced.
7 0
3 years ago
Read 2 more answers
How much is 3/4 of 120? And how much is 3/8 of 160?
RoseWind [281]
3/4 of 120
=3/4*120
=360/4
=90

3/8 of 160
=3/8*160
=480/8
=60
4 0
3 years ago
Read 2 more answers
In Exercises 5-7, find all the exact t-values for which the given statement is true,
bearhunter [10]

Answer:  See Below

<u>Step-by-step explanation:</u>

NOTE: You need the Unit Circle to answer these (attached)

5) cos (t) = 1

Where on the Unit Circle does cos = 1?

Answer: at 0π (0°) and all rotations of 2π (360°)

In radians:     t = 0π + 2πn

In degrees:   t = 0° + 360n

******************************************************************************

6)\quad sin (t) = \dfrac{1}{2}

Where on the Unit Circle does   sin = \dfrac{1}{2}

<em>Hint: sin is only positive in Quadrants I and II</em>

\text{Answer: at}\  \dfrac{\pi}{6}\ (30^o)\ \text{and at}\ \dfrac{5\pi}{6}\ (150^o)\ \text{and all rotations of}\ 2\pi \ (360^o)

\text{In radians:}\ t = \dfrac{\pi}{6} + 2\pi n \quad \text{and}\quad \dfrac{5\pi}{6} + 2\pi n

In degrees:    t = 30° + 360n  and  150° + 360n

******************************************************************************

7)\quad tan (t) = -\sqrt3

Where on the Unit Circle does    \dfrac{sin}{cos} = \dfrac{-\sqrt3}{1}\ or\ \dfrac{\sqrt3}{-1}\quad \rightarrow \quad (1,-\sqrt3)\ or\ (-1, \sqrt3)

<em>Hint: sin and cos are only opposite signs in Quadrants II and IV</em>

\text{Answer: at}\  \dfrac{2\pi}{3}\ (120^o)\ \text{and at}\ \dfrac{5\pi}{3}\ (300^o)\ \text{and all rotations of}\ 2\pi \ (360^o)

\text{In radians:}\ t = \dfrac{2\pi}{3} + 2\pi n \quad \text{and}\quad \dfrac{5\pi}{3} + 2\pi n

In degrees:    t = 120° + 360n  and  300° + 360n

4 0
2 years ago
Need help with this problem
Zanzabum

Answer:

C. Priya needs to charge at least $21 per bracelet.

Step-by-step explanation:

117b - 505 \ge 1952

Add 505 to both sides.

117b \ge 2457

Divide both sides by 117.

b \ge 21

Answer: C. Priya needs to charge at least $21 per bracelet.

7 0
3 years ago
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