Answer:
negative negative negative negative negative negative negative negative negative negative negative negative negative negative negative negative
- 1 1/10 + (-1 2/5)
- 1 1/10 + (-1 4/5)
-2 5/10
-2 1/2
Answer:
(1,3)
Step-by-step explanation:
The question is incomplete, here is the complete question:
Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.
<u>Answer:</u> The half life of the sample of phosphorus-32 is 
<u>Step-by-step explanation:</u>
The equation used to calculate the half life of the sample is given as:

where,
m(t) = amount of sample after time 't' = 356 g
= initial amount of the sample = 500 g
t = time period = 7 days
h = half life of the sample = ?
Putting values in above equation, we get:

Hence, the half life of the sample of phosphorus-32 is 
Answer:
He multiplyed 3x8 and 5x8 when it should be 3x8 and 5x1 because you but 1 under the 8 to make it into a fraction.
Step-by-step explanation: