Answer:
The volume is:
Step-by-step explanation:
See the sketch of the region in the attached graph.
We set the integral using washer method:
Notice here the radius of the washer is the difference of the given curves:
So the integral becomes:
We solve it:
Factor 
out and distribute the exponent (you can use FOIL):
Notice: 
So the integral becomes:
Then using the basic rule to evaluate the integral:
Simplifying a bit:
Then plugging the limits of the integral:
![\displaystyle\pi\left[\frac{4^3}{3}-\frac{4(4)^{5/2}}{5}+\frac{4^2}{2}-\left(\frac{1}{3}-\frac{4}{5}+\frac{1}{2}\right)\right]](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cpi%5Cleft%5B%5Cfrac%7B4%5E3%7D%7B3%7D-%5Cfrac%7B4%284%29%5E%7B5%2F2%7D%7D%7B5%7D%2B%5Cfrac%7B4%5E2%7D%7B2%7D-%5Cleft%28%5Cfrac%7B1%7D%7B3%7D-%5Cfrac%7B4%7D%7B5%7D%2B%5Cfrac%7B1%7D%7B2%7D%5Cright%29%5Cright%5D)
Taking the root (rational exponents):
![\displaystyle\pi\left[\frac{4^3}{3}-\frac{4(2)^{5}}{5}+\frac{4^2}{2}-\left(\frac{1}{3}-\frac{4}{5}+\frac{1}{2}\right)\right]](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cpi%5Cleft%5B%5Cfrac%7B4%5E3%7D%7B3%7D-%5Cfrac%7B4%282%29%5E%7B5%7D%7D%7B5%7D%2B%5Cfrac%7B4%5E2%7D%7B2%7D-%5Cleft%28%5Cfrac%7B1%7D%7B3%7D-%5Cfrac%7B4%7D%7B5%7D%2B%5Cfrac%7B1%7D%7B2%7D%5Cright%29%5Cright%5D)
Then doing those arithmetic computations we get:
To write the equation of a line, we use the equation: y = mx +b.
m is the slope of the line, which can be calculated using the equation:
m = (y2 - y1)/(x2 - x1)
We can choose any two points on the line to put into this equation. The red dots are at (0,0) and (-6,-2), so we will use those, but you would get the same answer by using any other pair of coordinates on the blue line.
m = (-2 - 0)/(-6 - 0) = 2/6 = 1/3
b is the y-intercept of the line. The y-intercept is the y-coordinate when the line crosses the y-axis. It crosses the y-axis at (0,0), so the y-intercept is 0.
Now, we plug our values back into the full equation to get the equation of the line.
y = mx + b
y = (1/3)x + 0
So the final answer is y = (1/3)x or y = x/3, depending on how you want to write it.
The surface area of a cylinder is define by the formula S.A.=2πrh+2<span>πr^2, where the first part of the formula refers to the lateral area, perimeter, or circumference and the second part to the area of the bases, which are circles.
On this exercise it is asked to find the lateral area of a cylinder whose radius is 6 cm, and has a height of 20cm. To find the lateral area of the cylinder you should substitute this values into the formula, S.A.=2</span>πrh, and as can be seen the answers are given in terms of <span>π or pi.
S.A.=2</span><span>πrh
S.A.=2</span><span>π(6cm)(20cm)
S.A.=2</span><span>π(120cm)
S.A.=240</span>π cm^2
The lateral area of the cylinder is 240<span>π cm^2 or in other words letter B from the given choices.</span>
8+ the product of 2 and a number to the third power, what it means 2×m cubed. So it is 8+2m (cubed)
keep in mind, that "t" is the time when the train at A station, left towards B station
they met, at some time "t", and by the time that happened, train from A
which started 3 hours earlier, had already covered "d" distance,
whatever that is
and the train coming from B, covered, 600-d, or the difference
