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pantera1 [17]
3 years ago
5

Write the ratio as a fraction, a decimal, and a percent. 51:75

Mathematics
1 answer:
irina [24]3 years ago
6 0
51:75

This is the same as 51/75.

Simplify by dividing 3 to the numerator and denominator:

17/25

Divide this to get a decimal:

17 / 25 = 0.68

Now multiply by 100 to get a percent:

0.68 * 100 = 68%
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In a dilation with a scale factor of 3/4 , the image is ___________ the pre image
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I need to find the area. (please help me quickly & the answer and explanation plz) POINTS: 15 please give real answers
Serggg [28]

Answer: 7.8

Step-by-step explanation:

you would multiply 3 x 2.6 and that would give you the answer

7 0
2 years ago
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JJill begins the summer with $500 in her savings account. Each week, she withdraws $20. Her brother, Sam,starts the summer with
meriva

Answer:

7th week

Step-by-step explanation:

Let us represent the number of weeks as x

Jill begins the summer with $500 in her savings account. Each week, she withdraws $20.

$500 - $20× x

500 - 20x

Her brother, Sam,starts the summer with $150 in his account. He adds $30 to his account each week.

$150 + $30 × x

150 + 30x

At what week will both Jill and Sam have the same amount in their account?

We solve this be Equating both Equations together

Jill = Sam

500 - 20x = 150 + 30x

Collect like terms

500 - 150 = 30x + 20x

350 = 50x

Divide both sides by 50

50x/50 = 350/50

x = 7 weeks

Therefore, at the 7 week, Jill and sam would have the same amount in their accounts

3 0
3 years ago
Hey sorry to bother you but what is (x+4)^2
guapka [62]
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4 0
3 years ago
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Determine the probability of selecting a two-child family with one boy and one girl assuming boys and girls are equally likely
Fittoniya [83]

Using the binomial distribution, it is found that there is a 0.5 = 50% probability of selecting a two-child family with one boy and one girl.

For each child, there are only two possible outcomes, either it is a boy, or it is a girl. The probability of a child being a boy or being a girl is independent of any other child, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • Two children, hence n = 2.
  • Equally as likely to be a boy or a girl, hence p = 0.5.

The probability of one of each is P(X = 1), hence:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{2,1}.(0.5)^{1}.(0.5)^{1} = 0.5

0.5 = 50% probability of selecting a two-child family with one boy and one girl.

A similar problem is given at brainly.com/question/24863377

3 0
3 years ago
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