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Luden [163]
4 years ago
5

Find the equation of thr line perpendicular to y= 3/2x+1 and passing through the point (5,1)

Mathematics
1 answer:
aliina [53]4 years ago
5 0

Answer:

y=-2/3x+13/3

Step-by-step explanation:

You might be interested in
What is the volume of a cone with radius 3.4 feet and altitude 4.8 feet?
Delvig [45]

Answer:

V≈58.11ft³

Step-by-step explanation:

that is the answer because you are trying to find the volume.

8 0
3 years ago
FIXED! HELP!Maria bought 1 2/5 pounds of lunch meat for $3.36. How much would 2 3/4 pounds of lunch meat cost? Enter your answer
Vsevolod [243]
We are going to want to change any mixed number into an improper fraction. 2 3/4 is 11/4 and 1 2/5 is 7/5.
We are going to set up a proportion where the lbs are on the top and the money is on the bottom. x is going to be how much it costs for 2 3/4 lbs of lunch meat.

(7/5)/3.36 = (11/4)/x
Cross multiplication \/
7/5x = 9.24
x = 6.60

As a final answer, the 2 3/4 lbs of lunch meat cost $6.60
5 0
4 years ago
Suppose the speeds of vehicles traveling on a highway are normally distributed and have a known population standard deviation of
ladessa [460]

Answer:

The margin of error for the confidence interval for the population mean with a 98% confidence level is 2.88 miles per hour.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.98}{2} = 0.01

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.01 = 0.99, so z = 2.326

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

Find the margin of error for the confidence interval for the population mean with a 98% confidence level.

M = 2.326*\frac{7}{\sqrt{32}} = 2.88

The margin of error for the confidence interval for the population mean with a 98% confidence level is 2.88 miles per hour.

5 0
3 years ago
By how much does a a^3-2a exceed a^2 + a -6
olganol [36]

Answer:

a³ - a² - 3a+ 6

Step-by-step explanation:

we are asked by how much does (a³-2a) exceed (a²+a-6)

in other words, we are being asked to find the difference between the 2 terms above.

Mathematically we are asked to find:

(a³-2a) - (a²+a-6)    (expand parentheses by distribution property)

=(a³-2a - a²- a + 6)

= a³ - a² - 3a+ 6    (answer)

8 0
3 years ago
WILL MARK BRANLIEST
Solnce55 [7]

Answer:

Try 9 x j(2 + 5)

4 0
3 years ago
Read 2 more answers
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