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Luden [163]
4 years ago
5

Find the equation of thr line perpendicular to y= 3/2x+1 and passing through the point (5,1)

Mathematics
1 answer:
aliina [53]4 years ago
5 0

Answer:

y=-2/3x+13/3

Step-by-step explanation:

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3 0
3 years ago
What is the value of y in y-5=3-9(y+2)
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so u are going to add like terms 3 and -18 which is -15. so the next step is going to be y-5=-9y-15 so u are going to add 5 to -5 and -15 to balance the equation and u will get -10 .  y=-9y -10. since u are multiplying -9 by y so have to expand it y= -9 * y -10. so u have to divide y by y to get y . -9-10= -19 soo y =-19


3 0
3 years ago
Idk how to do this 4x+y=1
ivolga24 [154]
4x+y=1
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6 0
3 years ago
5x + 10y = 18
SOVA2 [1]
5x + 10y = 18

x = y -6, we substitute this into first equation.

5x + 10y = 18

5*(y - 6) + 10y = 18

5y - 30 + 10y = 18

So it the last option from the top.
4 0
3 years ago
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Answer:

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