These problems are rather easy. What you need to remember is that the parallel line segments will always contain the same number so the angle (65) on b2 would be the same angle for a2, bt at. so now to find the angle for b1 and a1 so we would subtract 65( the angle for B2) by 180 (the angle for a line) which would come out to be 115.
i hope this helped you, if not heres a link to a website that explains what i tried to explain.
Answer:
4080
Step-by-step explanation:
I LOOOVE YOUR PROFILE PICCC
Answer:
we know that
[the lateral area of a right circular cone]=pi*r*l
where
r--------------> the radius of the circle part of the cone
l--------------> the side (slant height) of the cone
r=6 ft
h=8 ft
Step 1
find the slant height of the cone
which is determined by using Pythagoras, since the cross section is a right triangle.
l² = h²+ r²------------> l²=8²+6²-------> l²=64+36---------> l=10 ft
Step 2
find the lateral area
[the lateral area of a right circular cone]=pi*r*l--------> pi*6*10----> 188.4 ft²
the answer is 188.4 ft²
4a^5b^8 I hope this helps
