All categories

4 years ago

The answers

Mathematics

1 answer:

Vsevolod [243]4 years ago

7 0

Answer:

alternate exterior angles

Step-by-step explanation:

so are 2 & 8

You might be interested in

What is the upper bound and lower bound for 35.7

stepladder [879]

Answer:

tried.. sry if it is wrong...

Step-by-step explanation:

some examples for u..

Mark me the Brainliest..PLS

7 0

3 years ago

The final cost of a sale item is determined by multiplying the price on the tag by 75%. Which best describes the function that r

Lelechka [254]

Answer:

Option A) is correct.

Step-by-step explanation:

The final cost of a sale item is determined by multiplying the price on the tag by 75%.

So. if the final cost is represented by $F and the price on the tag is $t, then the relation between F and t will be

F = 0.75t.

This relation is linear since the ratio of the change in the final cost compared to the rate of change in the price tag is constant.

Therefore, option A) is correct. (Answer)

5 0

3 years ago

Read 2 more answers

Solve the following equation -2y-6=4

LenKa [72]

Answer:

Y= -5

Explanation: have an amazing day!!

3 0

3 years ago

The smallest object visible with your eyes is similar to the width of a piece of hair, which is 1×10−4 meters wide. Using an opt

Sloan [31]

Answer:

B. $5\times10^{2}$

Step-by-step explanation:

We are told that the smallest object visible with our eyes is similar to the width of a piece of hair, which is $1\times 10^{-4}$ meters wide.

Using an optical microscope, we can see items up to $2\times 10^{-7}$ meters wide.

To find the objects we can see with our eyes are how much larger than the objects we can see with an optical microscope, we can set an equation as:

$\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=\frac{1*10^{-4}}{2*10^{-7}}$

Using the exponent rule of quotient $\frac{a^m}{a^n}=a^{m-n}$ we will get,

$\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=\frac{1}{2}*10^{-4-(-7)}$

$\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=0.5*10^{-4+7}$

$\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=0.5*10^{3}$

$\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=0.5*10\times 10^{3-1}$

$\text{The object we can see with our eyes}=5\times10^{2}*\text{The objects we can see with microscope}$

Therefore, the objects we can see with our eyes are $5\times10^{2}$ times larger than the objects we can see with an optical microscope and option B is the correct choice.

3 0

3 years ago

See picture for problem. Please answer if you know

skelet666 [1.2K]

Answer: rx-sx= -2x^2

rx+sx=4x^2+8x

(r)(s)=3x^2+16x+16

Step-by-step explanation: Hopefully this helps! :)

4 0

3 years ago