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3 years ago

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A quality-conscious disk manufacturer wishes to know the fraction of disks his company makes which are defective. In earlier stu

dy, the population proportion was estimated to be 0.06. How long a sample would be required in order to estimate the fraction of disks produced which are defective at the 99% confidence level with an error of at most 0.02, Round your answer up to the next integer.

1 answer:

Elena L [17]3 years ago

6 0

Answer:

75

Step-by-step explanation:

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90 juniors took different SAT-II tests. 40% more students took the Chemistry test than took the History test, and 50% more stude

erastovalidia [21]

Answer:

Step-by-step explanation:

4.5x=90

x=20 history

28 chemistry

42 math

They add to 90.

History test=x

Chemistry test=1.4x

Math test=(1.5)(1.4)=2.1x

They add to 90

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3 years ago

. The time of a clock as seen in a mirror is 3:15. The correct time is

Oksana_A [137]

Answer:

3:15 cause a mirror cant change time

Step-by-step explanation:

go in ur mirror and look at the time did it somehow get darker or lighter???

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Use the figure to name a plane containing point <br> L.

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3 years ago

MARSVECTORCALC6 3.4.020. My Notes A rectangular box with no top is to have a surface area of 64 m2. Find the dimensions (in m) t

ioda

Answer:

We would have

$l =w =\frac{8\sqrt{3}}{3} \\h = \frac{8\sqrt{3}}{6}$

where " l " is length, " w" is width and "h" is height.

Step-by-step explanation:

Step 1

Remember that

Surface area for a box with no top = $lw+2lh+2wh = 64$

where " l " is length, " w" is width and "h" is height.

Step 2.

Remember as well that

Volume of the box = $l*w*h$

Step 3

We can now use lagrange multipliers. Lets say,

$F(l,w,h) = lwh$

and

$g(l,w,h) = lw+2lh+2wh = 64$

By the lagrange multipliers method we know that

$\nabla F = \lambda \nabla g$

Step 4

Remember that

$\nabla F = (wh,lh,lw)$

and

$\nabla g = (w+2h,l+2h , 2w+2l)$

So basically you will have the system of equations

$wh = \lambda (w+2h)\\lh = \lambda (l+2h)\\lw = \lambda (2w+2l)$

Now, remember that you can multiply the first eqation, by "l" the second equation by "w" and the third one by "h" and you would get

$lwh = l\lambda (w+2h)\\\\lwh = w\lambda (l+2h)\\\\lwh = h\lambda (2w+2l)$

Then you would get

$l\lambda (w+2h) = w\lambda (l+2h) = h\lambda (2w+2l)$

You can get rid of $\lambda$ from these equations and you would get

$lw+2lh = lw+2wh = 2wh+2lh$

And from those equations you would get

$l = w =2h$

Now remember the original equation

$lw+2lh+2wh = 64$

If we plug in what we just got, we would have

$l^{2} + l^{2} + l^2 = 64 \\3l^{2} = 64 \\l = w = \frac{8\sqrt{3} }{3} \\h = \frac{8\sqrt{3} }{6}$

7 0

3 years ago

Which statement describes the behavior of the function f(x)=3x/4-x?

Oksana_A [137]

Answer:

The graph approaches –3 as x approaches infinity. Option a is correct.

Step-by-step explanation:

The given function is

$f(x)=\frac{3x}{4-x}$

We have to find value of function as x approaches infinity. Take limit both sides as x approaches to infinity.

$\lim_{x\rightarrow \infty}f(x)=\lim_{x\rightarrow \infty}\frac{3x}{4-x}$

Taking x common from the denominator.

$\lim_{x\rightarrow \infty}f(x)=\lim_{x\rightarrow \infty}\frac{3x}{x(\frac{4}{x}-1)}$

Cancel out common factor x.

$\lim_{x\rightarrow \infty}f(x)=\lim_{x\rightarrow \infty}\frac{3}{\frac{4}{x}-1}$

Apply limits.

$\lim_{x\rightarrow \infty}f(x)=\frac{3}{\frac{4}{\infty}-1}$

$\lim_{x\rightarrow \infty}f(x)=\frac{3}{0-1}$

$\lim_{x\rightarrow \infty}f(x)=-3$

Therefore the graph approaches –3 as x approaches infinity.

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3 years ago

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