All categories

3 years ago

Please 30 points you will get!

Mathematics

1 answer:

Advocard [28]3 years ago

6 0

For each value of x in the domain, there is one corresponding value of y.

The relation is a function.

The range is from 3(-3)-4 = -13 to 3(4)-4 = 8.

Range: -13 ≤ y ≤ 8

You might be interested in

B) State a valid formula for multiplying out (A + B)(A − B)

Diano4ka-milaya [45]

(A+B)(A-B) = A^2-B^2.

It's equality constant

8 0

3 years ago

A pair of fair dice is cast. Let Edenote the event that the number landing uppermost on the first die is a 1 and let Fdenote the

iris [78.8K]

Answer:

They are not independent

Step-by-step explanation:

Given

E = Occurrence of 1 on first die

F = Sum of the uppermost occurrence in both die is 5

Required

Are E and F independent

First, we need to list the sample space of a roll of a die

$Event\ 1 = \{1,2,3,4,5,6\}$

Next, we list out the sample space of F

$Event\ 2 = \{2,3,4,5,6,7,3,4,5,6,7,8,4,5,\$

$6,7,8,9,5,6,7,8,9,10,6,7,8,9,10,11,7,8,9,10,11,12\}$

In (1): the sample space of E is:

$E = \{1\}$

So:

$P(E) = \frac{n(E)}{n(Event\ 1)}$

$P(E) = \frac{1}{6}$

In (2): the sample space of F is:

$F = \{5,5,5,5\}$

So:

$P(F) = \frac{n(F)}{n(Event\ 2)}$

$P(F) =\frac{4}{36}$

$P(F) =\frac{1}{9}$

For E and F to be independent:

$P(E\ and\ F) = P(E) * P(F)$

Substitute values for P(E) and P(F)

This gives:

$P(E\ and\ F) = \frac{1}{6} * \frac{1}{9}$

$P(E\ and\ F) = \frac{1}{54}$

However, the actual value of P(E and F) is 0.

This is so because $E = \{1\}$ and $F = \{5,5,5,5\}$ have 0 common elements:

So:

$P(E\ and\ F) = 0$

Compare $P(E\ and\ F) = \frac{1}{54}$ and $P(E\ and\ F) = 0$ .

These values are not equal.

Hence: the two events are not independent

6 0

3 years ago

I’m not sure how to do solving and graphing inequalities

Juliette [100K]

Answer:

its easy

Step-by-step explanation:

First you need to get your two numbers or more than to like for example 6 and 9 6<9 the alligator mouth would go to the 9 because its bigger and say for instances 9,10,5 it would be 9<10>5 ten is bigger than them all so there you go

7 0

3 years ago

If the probability of surviving a head on car accident at 55 mph is 0.097, then what is the probability of not surviving

BabaBlast [244]

The probability of not surviving a head-on car accident is: 0.903

Step-by-step explanation:

The probabilities of occurrence and non-occurrence of an event add up to one.

If p is the probability that an even will happen and q is the probability that it will not happen

Then

$p+q=1$

Here,

Probability of surviving = p = 0.097

Probability of not surviving = q = ?

$0.097 + q = 1\\q = 1 - 0.097\\q = 0.903$

The probability of not surviving a head-on car accident is: 0.903

Keywords: Probability, Inverse

Learn more about probability at:

#LearnwithBrainly

5 0

3 years ago

Insert parentheses to make the statement true <br> 21-8-6=7

Advocard [28]

(21-8)-6=7

and that's it

5 0

3 years ago