Answer:
The answer is

Step-by-step explanation:
To find an equation of a line given the slope and a point we use the formula

where
m is the slope
( x1 , y1) is the point
From the question the point is (−5, 6) and slope = 3
The equation of the line is

We have the final answer as

Hope this helps you
This is a quadratic equation whose graph is a parabola that opens down.
When does the rocket reach its highest point? Note that at that point it will stop ascending, momentarily stop, and then begin descending. Note also that that point is the vertex of the parabola.
The easiest way to find that time value is to use the formula t = -b/(2a).
Here, t at max height is t = -(144) / (2*[-16]) = 4.5 sec (answer.
What's the rocket's height there? To answer this, sub 4.5 sec for t in the given equation, <span>h(t) = -16t^2 + 144t.
Note: Please use " ^ " to indicate exponentiation:
</span> -16t^2 + 144t (not -16t2 + 144t)
Answer:
11p-18.
Step-by-step explanation:
Use vector arithmetic to simplify.
Answer:
The points are
= ( 0 , - 2 ) and
= ( - 3 , 0 )
These points is plotted on the x-y graph
Step-by-step explanation:
Given linear equation as :
4 x + 6 y = - 12
now, Let the points for the equation be
and
Now, From equation
For, x = 0
4 × 0 + 6 × y = - 12
Or, 0 + 6 × y = - 12
∴ y =
I.e y = - 2
So,
= ( 0 , - 2 )
Again
For, y = 0
4 × x + 6 × 0 = - 12
Or, 4 × x + 0 = - 12
∴ x =
I.e x = - 3
So,
= ( - 3 , 0 )
So, The points are
= ( 0 , - 2 ) and
= ( - 3 , 0 )
Now, These points is plotted on the x-y graph Answer