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Natalka [10]
3 years ago
7

Plzzzz help me but dont ansewer if you dont know it. 100 points

Mathematics
2 answers:
mylen [45]3 years ago
6 0

The first one is 2x-3y/2

The second one is 1/x+2

The third one is (2x-5y)/(2x+5y)

The fourth one is x^2/z^2

guapka [62]3 years ago
5 0
The first one is 2x-3y/2
The second one is 1/x+2
The third one is (2x-5y)/(2x+5y)
The fourth one is x^2/z^2
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Two to One

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What is bigger 24 fl. Oz. Or 8 cups?
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Find the product of (x − 5)^2.
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8 0
3 years ago
Math problem+Zoey, a Gelada Baboon, is tied to one of the outside corners of a regular hexagon-shaped research facility, where h
dexar [7]

Answer

The monkey will be able to cover an area of 22.86 meters which is equivalent to two sides and half of the building.

Step-by-step explanation:

The length of the monkeys rope = 75 feet long

Each side of the hexagon shaped facility = 30 feet

Note that, 1 feet = 0.3048 m

if we convert 30 feet to Meter, we have,

30 × 0.3048 = 9.144

Therefore, 30 + 30 +15 = 75 which is equivalent to the two side and half side of the hexagon shaped building

75 feet × 0.304 meter = 22.86 meters.

So the total area the monkey will be able to cover will be

= 22.86 Meters which is equivalent to two sides and half of the hexagon shape building.

8 0
3 years ago
A psychologist obtains a random sample of 2020 mothers in the first trimester of their pregnancy. The mothers are asked to play
leva [86]

Answer:

First of all, we need to determine the system of hypothesis, which must have a null and alternative hypothesis.

In all hypothesis proof procedure, we must work with the null one, rejecting it or accepting it. If we reject the null hypothesis, it will mean that our principal hypothesis is true.

According to the problem, the null hypothesis must be: H_{o} : u = 100; because it says that 100 is the normal mean that is used.

The alternative hypothesis must be: H_{a} : u > 100; because the question is asking if there's enough evidence to say that they children have a higher IQ than 100.

Then, we must calculate the P-value, which is the probability value that we are gonna use to accept or reject the null hypothesis. This P-value we can calculate it with the formula: Z=\frac{x-u}{\frac{o}{\sqrt{n} } }; where x is the sample mean, u is the hypothetical mean parameter, o is the sample deviation and n is the sample.

Extracting all values from the problem: x = 104.3; u = 100; o = 14 and n = 20.

Applying all values to the formula: Z=\frac{104.3 - 100}{\frac{14}{\sqrt{20} } } = \frac{4.3}{\frac{14}{ 4.5} }=\frac{4.3}{3.1}=1.4

Then, this Z-value will give us the P-value by using the Z-table with the 0.05 level of significance. In table attached, we can see that the result is 0.9265. However, the P-value is 1 - 0.9265 = 0.735. We need to do this subtraction because, the result 0.9265 belong to the bigger area (as it's shown is the image in blue colour), and we need the smaller area, which belong to the 0.05 level of significance.

<em>In this problems, if the P-value is more than the level of significance, the null hypothesis is accepted. If the P-value is less than the level of significance the null hypothesis is rejected.</em>

Therefore, there is no enough evidence to say that the sample children have higher IQs, because the P-value is higher than the level of significance. (0.735>0.05).

5 0
3 years ago
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