Write a quadratic function whose graph has a vertex of (3,2) and passes through the point (4,7). f(x)=
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Answer:
Step-by-step explanation:
Our friend asking what the actual function is has a point. I completed this under the assumption that what we have is:
and used the quotient rule to find the derivative, as follows:
and simplifying a bit:
and a bit more to:
and combining like terms:
and factor out the GFC in the numerator to get:
That's the derivative simplified. If we want f'(0), we sub in 0's for the x's in there and get the value of the derivative at x = 0:
which simplifies to
which translates to
The slope of the function is 11/4 at the point (0, -1/2)
Hello, one way to see it is as below
Another way is to notice that F'(x)=G'(x) means that F(x) and G(x) are only different from a real constant that we can note a, it means that
and then F(2)-F(1)=G(2)-G(1)
thanks