Answer:
0.55555555
Step-by-step explanation:
Answer:
a) (0.5256,0.5944)
c) Criticism is invalid
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 560
Proportion of mislabeled = 56%

a) 90% Confidence interval:


Putting the values, we get:

b) Interpretation of confidence interval:
We are 90% confident that the true proportion of all seafood in the country that is mislabeled or misidentified is between 0.5256 and 0.5944 that is 52.56% and 59.44%.
c) Validity of criticism
Conditions for validity:

Verification:

Both the conditions are satisfied. This, the criticism is invalid.
E+14 is 100000000000000, so 1.783864 times that is 178386400000000
Answer:
25.9365
Step-by-step explanation: