Write a quadratic function whose graph has a vertex of (3,2) and passes through the point (4,7). f(x)=

Mathematics

1 answer:

agasfer [191]3 years ago

7 0

Answer:

y=5(x-3)^2+2

Step-by-step explanation:

You plug the point into f(x)=a(x-3)^2+2... that already has already been solved for the vertex that you want. Then you swap it out for the solution you have solved for.

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Contains the x intercept of 4x-y=8 and the point (-4,3)

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