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3 years ago

PLEASE HELP !!!

Mathematics

1 answer:

solniwko [45]3 years ago

6 0

Answer: C.(z^3+1)^2

NO EXPLANATION??!?!?!?!?!??!?!??!??!??

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9 x 27 + 2 x 31 - 28 = n

Fiesta28 [93]

9×27+2×31-28= 7,567
n=7,567

5 0

3 years ago

If 60% of a number is 18 what is 90% of the number? PLEASE HELP!!

STALIN [3.7K]

60%_____18
90%______x

x = 90×18/60 = 27

4 0

3 years ago

PLEASE HELP ASAP <333 What is the sum of the geometric series ?

ankoles [38]

Answer:

Step-by-step explanation:

There are a couple of ways to do this. You could figure all four terms out and add them, which is likely the simplest way.

One: 6^(1 - 1) = 6^0 = 1

Two: 6^(2 - 1) = 6^1 = 6

Three: 6^(3 - 1) = 6^2 = 36

Four: 6^(4 - 1) = 6^3 = 216

Sum = 259

7 0

3 years ago

A hypothetical population consists of eight individuals ages 13, 14, 17, 20, 21, 22, 24, & 30 years.

Alika [10]

Complete Question

A hypothetical population consists of eight individuals ages 13 14 17 20 21 22 24 30 years.

A: what is the probability that a person in this population is a teenager?

B: what is the probability of selecting a participant who is at least 20 years old?

We have that probability that a person in this population is a teenager and probability of selecting a participant who is at least 20 years old is

From the question we are told

A hypothetical population consists of eight individuals ages 13, 14, 17, 20, 21, 22, 24, & 30 years.

P(T)=0.38
P(T')=0.63

Generally the equation for the probability that a person in this population is a teenager is mathematically given as

$P(T)=\frac{no of teens}{n}\\\\P(T)=\frac{3}{8}$

P(T)=0.38

Generally the equation for the probability of selecting a participant who is at least 20 years old is mathematically given as

$P(T)=\frac{ participants\ who\ is\ at\ least\ 20\ years old}{n}\\\\P(T)=\frac{5}{8}$

P(T')=0.63

For more information on this visit

brainly.com/question/11234923?referrer=searchResults

6 0

2 years ago

BRAINLIEST PLEASE HELP np If f(x)=-x^2+6x-1 and g(x)=3x^2-4x-1, find (f+g)(x)

raketka [301]

Answer:

$\large\boxed{B.\ (f+g)(x)=2x^2+2x-2}$

Step-by-step explanation:

$f(x)=-x^2+6x-1\\\\g(x)=3x^2-4x-1\\\\(f+g)(x)=f(x)+g(x)\\\\\text{substitute:}\\\\(f+g)(x)=(-x^2+6x-1)+(3x^2-4x-1)\\\\(f+g)(x)=-x^2+6x-1+3x^2-4x-1\qquad\text{combine like terms}\\\\(f+g)(x)=(-x^2+3x^2)+(6x-4x)+(-1-1)\\\\(f+g)(x)=2x^2+2x-2$

8 0

3 years ago