Answer:
13 seconds.
Step-by-step explanation:
Given

Required
Determine a reasonable solution for t
To do this, we equate h to 0.
becomes

Divide through by -4.9

Reorder the expression

Split
or 
This gives:
or 
But time can't be negative, So:

Answer: .
Step-by-step explanation:
Answer:
the distance between the two points is √130.
Step-by-step explanation:
a^2 + b^2 = c^2
a^2 = 9^2 = 81
b^2 = 7^2 = 49
c^2 = 81 + 49 = 130
c = √130

Synthetic division is used since the equation is of the third degree. The divisors of -3 are 1, -1, 3, +3. So:
| 2 -7 8 -3
<u>1 | 2 -5 3</u>
| 2 -5 3 0
<u> 1 | 2 -3 </u>
2 -3 0
So the factorization is (x-1)² (2x-3)=0. So:


Synthetic division is used since the equation is of the third degree. The divisors of -4 are 1, -1, 2, -2, 4, -4. So:
| 1 -1 0 -4
<u>2 | 2 2 </u>
1 2 2 0
So the factorization is (x-2)(x²+x+2)=0 . When calculating the discriminant of the trinomial, it is concluded that it has no roots since the result is negative. So you only have one solution.


Synthetic division is used since the equation is of the third degree. The divisors of 2 are 1, -1, 2, -2. So:
| 6 7 9 2
<u>-2 | -12 10 -2</u>
6 -5 1 0
So the factorization is (x+2)(6x²-5x+1)=0 . The quadratic equation is solved by the general formula:

