Answer:
Yes, both np and n(1-p) are ≥ 10
Mean = 0.12 ; Standard deviation = 0.02004
Yes. There is a less than 5% chance of this happening by random variation. 0.034839
Step-by-step explanation:
Given that :
p = 12% = 0.12 ;
Sample size, n = 263
np = 263 * 0.12 = 31.56
n(1 - p) = 263(1 - 0.12) = 263 * 0.88 = 231.44
According to the central limit theorem, distribution of sample proportion approximately follow normal distribution with mean of p = 0.12 and standard deviation sqrt(p*(1 - p)/n) = sqrt (0.12 *0.88)/n = sqrt(0.0004015) = 0.02004
Z = (x - mean) / standard deviation
x = 22 / 263 = 0.08365
Z = (0.08365 - 0.12) / 0.02004
Z = −1.813872
Z = - 1.814
P(Z < −1.814) = 0.034839 (Z probability calculator)
Yes, it is unusual
0.034 < 0.05 (Hence, There is a less than 5% chance of this happening by random variation.
Answer:
can u attach the diagram
Step-by-step explanation:
Answer:
A. between 3.0 and 3.5 and between 4.0 and 4.5
Step-by-step explanation:
The idea here is that if a function is continuous and you have points on opposite sides of the x-axis, then there must be a zero-crossing between those points. As the table and graph show, ...
... (3.0, 4.0) and (3.5, -0.2)
are points on opposite sides of the x-axis. So, there must be a zero crossing between x=3.0 and x=3.5.
Likewise, ...
... (4.0, -0.8) and (4.5, 0.1)
are points on opposite sides of the x-axis. So, there must be a zero-crossing between x=4.0 and x=4.5
The appropriate answer choice lists both of these possible zero crossings.
The area of the rhombus is 65.79