If the equation x² + 16x + c = 0 has only one real solution, the value of c is equal to 64.
<h3>Discriminant: </h3>
The quadratic formula includes the discriminant, which comes after the square root. The discriminant of a quadratic equation is important because it indicates the quantity and kind of solutions.
The formula for the Discriminant of a Quadratic Equation ax²+bx +c = 0 is given by
<h3> Discriminant Δ = b² - 4ac </h3>
Here we have
x² + 16x + c = 0 equation has only one real solution
Compare given equation with ax²+ bx + c = 0
=> a = 1, and b = 16
As we know when an equation has only one real solution
then its Discriminant will be equal to zero
=> b² - 4ac = 0
By the above values,
=> 16² - 4(1)c = 0
=> 256 - 4c = 0
=> 4c = 256
=> c = 256/4
=> c = 64
Therefore,
If the equation x² + 16x + c = 0 has only one real solution, the value of c is equal to 64.
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The given question is wrong.
Question:
Which expression is equivalent to the given expression using commutative property of addition? 2(x + b) + 3(xa).
Answer:
Option C:
3(xa) + 2(x + b)
Solution:
Given expression is 2(x + b) + 3(xa).
To find the equivalent expression using commutative property of addition.
Let us first define the commutative property of addition.
a + b = b + a
You can add in any order.
Now, write the given expression using commutative property.
2(x + b) + 3(xa) = 3(xa) + 2(x + b)
Option C is the correct answer.
Hence 3(xa) + 2(x + b) equivalent expression using commutative property of addition.
The ladder must be 9.4 ft to reach the top of the building
Here, we want to get the length of the ladder that will reach the top of the building
Firstly, we need a diagrammatic representation
We have this as;
As we can see, we have a right triangle with the hypotenuse being the length of the ladder
We simply will make use of Pythagoras' theorem which states that the square of the hypotenuse is equal to the sum of the squares of the two other sides
Thus, we have;
![\begin{gathered} x^2=5^2+8^2 \\ x^2=\text{ 25 + 64} \\ x^2\text{ = 89} \\ x=\text{ }\sqrt[]{89} \\ x\text{ = 9.4 ft} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20x%5E2%3D5%5E2%2B8%5E2%20%5C%5C%20x%5E2%3D%5Ctext%7B%2025%20%2B%2064%7D%20%5C%5C%20x%5E2%5Ctext%7B%20%3D%2089%7D%20%5C%5C%20x%3D%5Ctext%7B%20%7D%5Csqrt%5B%5D%7B89%7D%20%5C%5C%20x%5Ctext%7B%20%3D%209.4%20ft%7D%20%5Cend%7Bgathered%7D)
Answer:
No because when you set it up it would be 11/9.4 which equals 1.17
Then you do the other side, 10/8.4 which equals 1.19
And 1.17 doesn't equal 1.19 so they are not similar
Cos(t/2) I got .45 is that what you were looking for or do I need to plug it into the equation up top? can you give me notes of something? cos( -9/11/2) = .45
