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3 years ago

Determine the area of e 1. 4inch

Mathematics

1 answer:

Afina-wow [57]3 years ago

8 0

16inches i’m pretty sure

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How to do I solve this

padilas [110]

4. 2b-6+3b=
5b-6=143
5b=143+6
5b=149

b=149
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5

5 0

3 years ago

Use the quadratic formula to solve the equation -4x^2-3x+2=0

Karolina [17]

The quadratic formula is hard to type on this
3 (+ , -) (sqroot of 41)
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8

7 0

3 years ago

Read 2 more answers

Jack is mixing a cleaning solution that is 12% bleach.After mixing the solution,jack has 150 ounces of cleaning solution.how man

marysya [2.9K]

To solve for the ounces of bleach that Jack used, we utilize the formula below

Bleach = (Percentage of bleach)*(Total ounces of cleaning solution)
Bleach = 0.12*150 ounces
Bleach = 18 ounces

<em>ANSWER: 18 ounces of bleach</em>

5 0

2 years ago

The yellow boxes on the bottom are the answers. Please help TYSM

sveticcg [70]

Answer:

$1.\ 8p = 64, p =8$

$2. -\dfrac{w}{4} = 8, w = -32$

$3. -5c = -20, c =4$

$4.\ 9m=45, m = 5$

$5. \dfrac{b}{25} = -3, b =-75$

$6. \dfrac{d}{-2} = 20, d=-40$

Step-by-step explanation:

Now let us see the detailed solution of each part:

Part 1:

$8p -15 = 49\\\Rightarrow 8p =49+15\\\Rightarrow 8p = 64\\\Rightarrow p =8$

Part 2:

$\dfrac{-w}{4}+18=26\\\Rightarrow \dfrac{-w}{4} = 26-18\\\Rightarrow \dfrac{-w}{4} = 8\\\Rightarrow -w = 8 \times 4\\\Rightarrow w =-32$

Part 3:

$-5c-15=-35\\\Rightarrow -5c = -35 +15\\\Rightarrow -5c = -20\\\Rightarrow c = 4$

Part 4:

$9m +10=55\\\Rightarrow 9m =55-10\\\Rightarrow 9m =45\\\Rightarrow m =5$

Part 5:

$\dfrac{b}{25}-83=-86\\\Rightarrow \dfrac{b}{25} = -86 +83\\\Rightarrow \dfrac{b}{25} = -3\\\Rightarrow b = -75$

Part 6:

$\dfrac{d}{-2}+85=105\\\Rightarrow \dfrac{d}{-2} = 105-85\\\Rightarrow \dfrac{d}{-2} = 20\\\Rightarrow d=20 \times -2\\\Rightarrow d =-40$

Please refer to attached image for the answers.

7 0

2 years ago

Find the illegal values of c in the multiplication statement c^2-3c-10/c^2+5c-14 times c^2-c-2/c^2-2c-15

Citrus2011 [14]

Answer: c ≠ {-7, -3, 2, 5}

<u>Step-by-step explanation:</u>

$\frac{c^{2} - 3c - 10}{c^{2} + 5c - 14} * \frac{c^{2} - c - 2}{c^{2} - 2c - 15}$

= $\frac{(c - 5)(c + 2)}{(c + 7)(c - 2)} * \frac{(c - 2)(c + 1)}{(c - 5)(c +3)}$

restrictions:

c + 7 ≠ 0 c - 2 ≠ 0 c - 5 ≠ 0 c + 3 ≠ 0

c ≠ -7 c ≠ 2 c ≠ 5 c ≠ -3

3 0

3 years ago