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Papessa [141]
3 years ago
6

3 and 1/3 - 2 and 1/5

Mathematics
1 answer:
Natalija [7]3 years ago
8 0

Answer:

1.13333333333

1.13

Step-by-step explanation:

1: Gather all the numbers

2: Use a calculator to subtract the numbers

3: Answer is 1.13

<em><u>Hope this helps.</u></em>

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If y varies directly as x, and y is 18 when x is 5, which expression can be used to find the value of y when x is 11?
Leokris [45]

Answer: The value of y is 39.6 when x = 11 and the required expression is y(11) = 39.6

Step-by-step explanation:

Since we have given that

y varies directly as x.

If y = 18, when x = 5.

So, we need to find the value of y when x is 11.

According to question, we get that

\dfrac{y}{x}=\dfrac{18}{5}=\dfrac{y}{11}\\\\18\times 11=5y\\\\198=5y\\\\\dfrac{198}{5}=y\\\\y=39.6

Hence, the value of y is 39.6 when x = 11 and the required expression is y(11) = 39.6

5 0
3 years ago
8) What is the common ratio for this sequence?
Naddika [18.5K]

Step-by-step explanation:

it will 2.5 this is right answer option D

6 0
2 years ago
(x + x - 8x? - 13x - 7) = (x + 2)
WINSTONCH [101]
Why is there a question mark?
7 0
3 years ago
The volume of a cylindrical soup can is represented by the expression πr3 + 7πr2, where r is the radius of the cylinder. Which s
Ganezh [65]

Answer:

Step-by-step explanation:

Given the volume of the cylindrical soup expressed as V = πr³+ 7πr²

From V = πr³ + 7πr²;

factor out the common variable

V = πr³ + 7πr²

V = πr²(r+7) ... 1

The original volume of a cylinder V =  πr²h .... 2 where;

r is the radius of the cylinder

h is the height of the cylinder

Equating equation 1 and 2, we will have;

πr²(r+7)  =  πr²h

Divide both sides by  πr²

πr²(r+7)/ πr² = πr²h/ πr²

r+7 = h

h = r+7

<em>Hence the factor in the context given is equivalent to the height of the cylinder written as a function of its radius r</em>.<em> The statement means that the height of the cylindrical soup is 7 more than its radius.</em>

<em></em>

5 0
3 years ago
If E F = 7 , A C = 16 , and A F = 9
Vilka [71]

Answers:

CB = 14

GF = 8

FB = 9

EF is parallel to CB

====================================

Explanations:

Points E and F are midpoints of their respective sides. They form the midsegment EF. Because EF is a midsegment, A midsegment is half the length of its parallel counterpart, so CB is two times longer than EF. If EF is 7 units long, then CB = 2*EF = 2*7 = 14

For similar reasons, GF is parallel to AC. If AC = 16, then half of that is GF = (1/2)*AC = 0.5*16 = 8.

FB = FA = 9 as these segments have the same single tickmark to indicate they are the same length

EF is parallel to CB because EF is a midsegment, and this is one of the properties of being a midsegment. We can show that quadrilateral EGBF is a parallelogram to help prove this.

8 0
3 years ago
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