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3 years ago

Rule start at 5 and 1/2 add 1 1/5

Mathematics

1 answer:

Margaret [11]3 years ago

4 0

Answer:

The solution is $6\frac{7}{10}$ .

Step-by-step explanation:

It is given that rule start at $5\frac{1}{2}$ add $1\frac{1}{5}$ .

From the given information, we get the expression

$5\frac{1}{2}+1\frac{1}{5}$

Simplify the complex fraction.

$\frac{10+1}{2}+\frac{5+1}{5}$

$\frac{11}{2}+\frac{6}{5}$

Taking LCM, we get

$\frac{11\times 5+6\times 2}{2\times 5}$

$\frac{55+12}{10}$

$\frac{67}{10}$

$6\frac{7}{10}$

Therefore the he solution is $6\frac{7}{10}$ .

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Answer:

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Step-by-step explanation:

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2 years ago

X + 7 = 18 what is the value of x

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Answer:

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3 years ago

The average ticket price for a concert at the opera house was $50. The average attendance was 4000. When the ticket price was ra

kotegsom [21]

Answer

given,

opera house ticket = $50

attendance = 4000 persons

now,

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attendance = 3800 person

assuming these are the points on the demand curve

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using point slope formula

$p-50 = \dfrac{50-52}{4000-3800}(x - 4000)$

$p-50 = \dfrac{-2}{200}(x - 4000)$

$p-50 = \dfrac{-x}{100}+ 40$

$p = \dfrac{-x}{100}+ 90$

R(x) = x . p

$R(x) = x (\dfrac{-x}{100}+ 90)$

$R(x) = \dfrac{-x^2}{100}+ 90x)$

$\dfrac{d}{dx}(R(x)) = \dfrac{d}{dx}(\dfrac{-x^2}{100}+ 90x))$

$\dfrac{d}{dx}(R(x)) = (\dfrac{-2x}{100})+90)$

at $\dfrac{d}{dx}(R(x)) = 0$

$\dfrac{-2x}{100}= -90$

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$\dfrac{d^2}{d^2x}(R(x)) = -ve$

hence at x =4500 the revenue is maximum

for maximum revenue ticket price will be

$p = \dfrac{-4500}{100}+ 90$

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4 years ago

|-5| |-9| <br> is it greater, less than, or equal to<br> <, >, = ??!?!

Katyanochek1 [597]

Answer:

< (less than)

Step-by-step explanation:

since abs value changes it to positive it would be

5 and 9

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3 years ago

Read 2 more answers