A plan that costs $29.99 another company $19.99 and $0.35 during nights and weekends for what numbers of night and weekend does
2 answers:
Answer:
<em>29 minutes more</em>
Step-by-step explanation:
Let m represent minutes
changing the statement to algebra, since the second company charges a different rate at night and weekend we have the equation below;
$19.99 + $0.35m > $29.99
Subtract 19.99 from both sides to isolate m and we have;
$19.99 -$19.99 + $0.35 > $29.99 - $19.99
= $0,35m > $10.00
Divide both side by 0.35 to obtain the value of m;
>
= m > 28.57
<em>m ⩾ 29 minutes</em>
<em>The second company's will be twenty nine minutes or more costlier than the first company</em>
Answer:
Approximately:
n≥29
So the number of night and weekend that the second company's plan cost more then the first company's plan are ≥ 29
Step-by-step explanation:
let say n is the numbers of night and weekend that the second company's plan cost more then the first company's plan.
Since second company has $19.99 and $0.35 during nights and weekend and it is grater than the first company which costs $29.99.
According to the above condition, We will get the equation:
Solving the above equation:
Approximately:
n≥29
So the number of night and weekend that the second company's plan cost more then the first company's plan are ≥ 29
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