Evaluate 3x for x = −2, x = 1, and x = 3. Question 18 options: A) 1∕3, 0, 9 B) 1∕9, 3, 27 C) 9, 3, 27 D) 1∕9, 9, 27
icang [17]
Answer: B) 1/9, 3, 27
Step-by-step explanation:
Here, we need to evaluate 
for 
So, we substitute values of x in the given function.
At x= -2, we have
![3^{-2}=\dfrac{1}{3^2}=\dfrac{1}{9}\ \ \ [\because\ a^{-n}=\dfrac{1}{a^n}]](https://tex.z-dn.net/?f=3%5E%7B-2%7D%3D%5Cdfrac%7B1%7D%7B3%5E2%7D%3D%5Cdfrac%7B1%7D%7B9%7D%5C%20%5C%20%5C%20%5B%5Cbecause%5C%20a%5E%7B-n%7D%3D%5Cdfrac%7B1%7D%7Ba%5En%7D%5D)
At x= 1, we have
At x= 3
So, the values of for
Thus, the correct answer is B) 1/9, 3, 27
The value of the length of the rhombus will be found as follows:
cos θ=adjacent /hypotenuse
θ=108/2=54°
adjacent = 9/2=4.5 inch
hypotenuse=length of the rhombus
thus
cos 54=9/x
x=4.5/cos 54
x=7.6558~8 inches
the answer is 8 inches
Answer:
x = ± sqrt(43)
Step-by-step explanation:
2x^2 - 28 = x^2 + 15
Subtract x^2 from each side
2x^2-x^2 - 28 = x^2-x^2 + 15
x^2 -28 = 15
Add 28 to each side
x^2 - 28 +28= 15+28
x^2 = 43
Take the square root of each side
sqrt(x^2) = ± sqrt(43)
x = ± sqrt(43)
(which is angle p? 2k or k+10?)
