Answer:
The value of N that satisfies the equation is
Step-by-step explanation:
First we open the factorial of 12, to simplify the expression:
12! = 12*11*10*9!
So
5!*9! = 12!*N
5!*9! = 12*11*10*9!N
12*11*10N = 5!
Now we open the factorial of 5. So
12*11*10*N = 5*4*3*2*1
Since 5*2 = 10, 4*3 = 12, we have that:
12*11*10*N = 10*12*1
Now, simplifying by 10*12
11N = 1
This is the value of N that satisfies the equation
Answer:
the dimensions that will minimize the cost of constructing the box is:
a = 5.8481 in ; b = 5.848 in ; c = 10.234 in
Step-by-step explanation:
From the information given :
Let a be the base if the rectangular box
b to be the height and c to be the other side of the rectangular box.
Then ;
the area of the base is ac
area for the front of the box is ab
area for the remaining other sides ab + 2cb
The base of the box is made from a material costing 8 ac
The front of the box must be decorated, and will cost 10 ab
The remainder of the sides will cost 4 (ab + 2cb)
Thus ; the total cost C is:
C = 8 ac + 10 ab + 4(ab + 2cb)
C = 8 ac + 10 ab + 4ab + 8cb
C = 8 ac + 14 ab + 8cb ---- (1)
However; the volume of the rectangular box is V = abc = 350 in³
If abc = 350
Then b =
replacing the value for c in the above equation (1); we have :
Differentiating C with respect to a and c; we have:
--- (2)
---(3)
From (2)
----- (4)
From (3)
-----(5)
Replacing the value of a in 5 into equation (4)
From (5)
-----(5)
a = 5.8481
Recall that :
b =
b =
b =5.848
Therefore ; the dimensions that will minimize the cost of constructing the box is:
a = 5.8481 in ; b = 5.848 in ; c = 10.234 in