What is the y-intercept in the equation y=4x-3?
2 answers:
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Let , a, b and c be the length of three sides of triangle, represented in terms of vectors as .
Now, vector of same Magnitude acts as normal vector to each side.
So, equation of any vector p having normal q is given by
Now sum of three vector and it's normal is given as
Cross product of two identical vectors is Zero.
Answer:
I can not solve it in the system of the image, but i will give you the graph so you can copy it, or at least see how it is done.
First, we have the lines:
y = (1/3)*x + 6
y = (-5/3)*x - 6
To graph these lines, you must find two points for the lines and then draw a line that connects the points.
To do it, you can evaluate each line in two different values of x, for example for the first line we can have:
y(0) = (1/3)*0 + 6 = 6 (then we have the point (0, 6))
y(3) = (1/3)*3 + 6 = 7 (then we have the point (3, 7))
And for the second line, we will have:
y(0) = (-5/3)*0 - 6 = -6 (then we have the point (0, -6))
y(3) = -(5/3)*3 - 6 = -11 (then we have the point (-3, -11))
Now with those points we can graph the lines, and the solution of the system of equation will be the point where the two lines intersect.
The graphs of the lines are shown below:
Where the grey line is the first one, and the green is the second.
In the graph, you can see that the lines intersect in the point (-6, 4)
Then the solution for the system is x = -6, and y = 4.
