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2 years ago

Use words and math to explain why these two expressions are equivalent.

Mathematics

2 answers:

mote1985 [20]2 years ago

8 0

Answer:

See explanation

Step-by-step explanation:

Let’s manipulate 3h+2-6+5h to show how it is equal to 2(4h-2)

Combine like-terms:

3h+2-6+5h = 8h-4

Then, factor out the greatest common factor (in this case it’s 2):

8h-4 = 2(4h-2)

If you want to verify how to above is true, just combine them again!

Sunny_sXe [5.5K]2 years ago

5 0

Answer:

here

Step-by-step explanation:

when given the first set, you combine like terms so you add 5h and 3h together and -6 and 2 are combined, so the first one is 8h -4. The second set you distribute 2 to 4h and -2 getting you 8h and -4 as well

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39x38 multiply using partial prodcuts

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39 x 10
= 390

39 x 40 (390 x 4)
= 1,560

39 x 2
= 78

1,560 - 78
= 1,482

ANSWER: 1,482

4 0

2 years ago

If there are 23 students in your class, and your teacher is pulling random names from a hat, what is the probability that your n

krok68 [10]

If the teacher isn't putting the names back in the hat then it would be 1/21 if she is then 1/23

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2 years ago

Read 2 more answers

PLEASE HELP ME NOW URGENT

timama [110]

ANSWER

$y = 3 \pm \sqrt{21}$

EXPLANATION

The quadratic equation is:

${y}^{2} - 6y - 12 = 0$

Group variable terms:

${y}^{2} - 6y = 12$

Add the square of half, the coefficient of y to both sides.

${y}^{2} - 6y + ( - 3) ^{2} = 12 + ( - 3) ^{2}$

${y}^{2} - 6y + 9= 12 + 9$

The LHS us now a perfect square trinomial:

${(y - 3)}^{2}= 21$

Take square root:

$y - 3 = \pm \sqrt{21}$

$y = 3 \pm \sqrt{21}$

The first choice is correct.

8 0

3 years ago

Read 2 more answers

You are designing a miniature golf course and need to calculate the surface area and volume of many of the objects that will be

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a. To solve the first part, we are going to use the formula for the surface area of a sphere: $A=4 \pi r^2$
where
$A$ is the surface area of the sphere
$r$ is the radius of the sphere
We know from our problem that $r=5ft$ ; so lets replace that value in our formula:
$A=4 \pi (5ft)^2$
$A=314.16ft^2$

To solve the second part, we are going to use the formula for the volume of a sphere: $V= \frac{4}{3} \pi r^3$
Where
$V$ is the volume of the sphere
$r$ is the radius
We know form our problem that $r=5ft$ , so lets replace that in our formula:
$V= \frac{4}{3} \pi (5ft)^3$
$V=523.6ft^3$

We can conclude that the surface area of the sphere is 314.16 square feet and its volume is 523.6 cubic feet.

b. To solve the first part, we are going to use the formula for the surface area of a square pyramid: $A=a^2+2a \sqrt{ \frac{a^2}{4} +h^2}$
where
$A$ is the surface area
$a$ is the measure of the base
$h$ is the height of the pyramid
We know form our problem that $a=8ft$ and $h=12ft$ , so lets replace those value sin our formula:
$A=(8ft)^2+2(8ft) \sqrt{ \frac{(8ft)^2}{4} +(12ft)^2}$
$A=266.39ft^2$

To solve the second part, we are going to use the formula for the volume of a square pyramid: $V=a^2 \frac{h}{3}$
where
$V$ is the volume
$a$ is the measure of the base
$h$ is the height of the pyramid
We know form our problem that $a=8ft$ and $h=12ft$ , so lets replace those value sin our formula:
$V=(8ft)^2 \frac{(12ft)}{3}$
$V=256ft^3$

We can conclude that the surface area of our pyramid is 266.39 square feet and its volume is 256 cubic feet.

c. To solve the first part, we are going to use the formula for the surface area of a circular cone: $A= \pi r(r+ \sqrt{h^2+r^2}$
where
$A$ is the surface area
$r$ is the radius of the circular base
$h$ is the height of the cone
We know form our problem that $r=5ft$ and $h=8ft$ , so lets replace those values in our formula:
$A= \pi (5ft)[(5ft)+ \sqrt{(8ft)^2+(5ft)^2}]$
$A=226.73ft^2$

To solve the second part, we are going to use the formula for the volume os a circular cone: $V= \pi r^2 \frac{h}{3}$
where
$V$ is the volume
$r$ is the radius of the circular base
$h$ is the height of the cone
We know form our problem that $r=5ft$ and $h=8ft$ , so lets replace those values in our formula:
$V= \pi (5ft)^2 \frac{(8ft)}{3}$
$V=209.44ft^3$

We can conclude that the surface area of our cone is 226.73 square feet and its surface area is 209.44 cubic feet.

d. To solve the first part, we are going to use the formula for the surface area of a rectangular prism: $A=2(wl+hl+hw)$
where
$A$ is the surface area
$w$ is the width
$l$ is the length
$h$ is the height
We know from our problem that $w=6ft$ , $l=10ft$ , and $h=16ft$ , so lets replace those values in our formula:
$A=2[(6ft)(10ft)+(16ft)(10ft)+(16ft)(6ft)]$
$A=632ft^2$

To solve the second part, we are going to use the formula for the volume of a rectangular prism: $V=whl$
where
$V$ is the volume
$w$ is the width
$l$ is the length
$h$ is the height
We know from our problem that $w=6ft$ , $l=10ft$ , and $h=16ft$ , so lets replace those values in our formula:
$V=(6ft)(16ft)(10ft)$
$V=960ft^3$

We can conclude that the surface area of our solid is 632 square feet and its volume is 960 cubic feet.

e. Remember that a face of a polygon is a side of polygon.
- A sphere has no faces.
- A square pyramid has 5 faces.
- A cone has 1 face.
- A rectangular prism has 6 faces.
Total faces: 5 + 1 + 6 = 12 faces

<span>We can conclude that there are 12 faces in on the four geometric shapes on the holes.
</span>
f. Remember that an edge is a line segment on the boundary of the polygon.
- A sphere has no edges.
- A cone has no edges.
- A rectangular pyramid has 8 edges.
- A rectangular prism has 12 edges.
Total edges: 8 + 20 = 20 edges

Since we have 20 edges in total, we can conclude that your boss will need 20 brackets on the four shapes.

g. Remember that the vertices are the corner points of a polygon.
- A sphere has no vertices.
- A cone has no vertices.
- A rectangular pyramid has 5 vertices.
- A rectangular prism has 8 vertices.
Total vertices: 5 + 8 = 13 vertices

We can conclude that there are 0 vertices for the sphere and the cone; there are 5 vertices for the pyramid, and there are are 8 vertices for the solid (rectangular prism). We can also conclude that your boss will need 13 brackets for the vertices of the four figures.

7 0

3 years ago

If the number of roaches triples every day, and there are 10 to start with, write an equation to represent this situation. How m

victus00 [196]

Answer:

430,467,210

Step-by-step explanation:

ur answer maybe idk

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3 years ago