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Westkost [7]
3 years ago
5

How do you write y = 1/4x + 10 in standard form using integers

Mathematics
1 answer:
never [62]3 years ago
3 0

Answer:

It's would be x- 4y=-40

Step-by-step explanation:


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An employee worked 160.5 hours in May, 160.4 hours in May, 165.75 hours in June and 152.25 hours in July.
Fudgin [204]
486.65 is the answer to the question
3 0
3 years ago
An acute triangle has side lengths 21 cm, x cm, and 2x cm. if 21 is one of the shorter sides of the triangle, what is the greate
madam [21]

Given that the sides of the acute triangle are as follows:
21 cm
x cm
2x cm

Stated that 21 cm is one of the shorter sides of the triangle2x is greater than x, so it follows that 2x MUST be the longest side


For acute triangles, the longest side must be less than the sum of the 2 shorter sides
Therefore, 2x < x + 21cm
2x – x < 21cm
x < 21cm

If x < 21cm, then 2x < 42cm
Therefore, the longest possible length for the longest side is 42cm
8 0
3 years ago
Read 2 more answers
Fill in the blank. Using the number line below, the plotted number is when rounded to the nearest thousand.​
prisoha [69]

Answer:

5000

Step-by-step explanation:

if its 5 or more round up. If it's 4 or less round down

6 0
2 years ago
PLEASE HELP ME I BEG I WILL GIVE BRAINLIEST
ohaa [14]

Answer:

Mean = (2.2 + 2.4 + 2.5 + 2.5 + 2.6 + 2.7)/6 = 2.48

Standard deviation = √(summation(x - mean)²/n

n = 6

Summation(x - mean)² = (2.2 - 2.48)^2 + (2.4 - 2.48)^2 + (2.5 - 2.48)^2 + (2.5 - 2.48)^2 + (2.6 - 2.48)^2 + (2.7 - 2.48)^2 = 0.1484

Standard deviation = √(0.1484/6

s = 0.16

Standard error = s/√n = 0.16/√6 = 0.065

Part B

Confidence interval is written as sample mean ± margin of error

Margin of error = z × s/√n

Since sample size is small and population standard deviation is unknown, z for 98% confidence level would be the t score from the student t distribution table. Degree of freedom = n - 1 = 6 - 1 = 5

Therefore, z = 3.365

Margin of error = 3.365 × 0.16/√6 = 0.22

Confidence interval is 2.48 ± 0.22

Part C

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

H0: µ = 2.3

For the alternative hypothesis,

H1: µ > 2.3

This is a right tailed test

Since the number of samples is small and no population standard deviation is given, the distribution is a student's t.

Since n = 6

Degrees of freedom, df = n - 1 = 6 - 1 = 5

t = (x - µ)/(s/√n)

Where

x = sample mean = 2.48

µ = population mean = 2.3

s = samples standard deviation = 0.16

t = (2.48 - 2.3)/(0.16/√6) = 2.76

We would determine the p value using the t test calculator. It becomes

p = 0.02

Assuming significance level, alpha = 0.05.

Since alpha, 0.05 > than the p value, 0.02, then we would reject the null hypothesis. Therefore, At a 5% level of significance, the sample data showed significant evidence that the mean absolute refractory period for all mice when subjected to the same treatment increased.

Step-by-step explanation:

7 0
3 years ago
Inequalities &amp; problem solving<br>|3-2x/3|&gt;5
shepuryov [24]
Work: 2x/2 > 5/2 =2.5. answer-2.5
5 0
3 years ago
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