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4 years ago

What is the width of the pond?

Mathematics

2 answers:

Semenov [28]4 years ago

6 0

Answer:

255 ft

Step-by-step explanation:

We will use trigonometry to solve this.

From the angle we will use the side provided and the side we want to find. The side provided is adjacent to the angle. The side we want to find is opposite to it. Thus, we will use tan because tan uses opposite/adjacent.

This means that tan60 = x/144

tan60 * 144 = x

x = 255

The width of the pond is 255 ft.

Leona [35]4 years ago

5 0

Answer:

Step-by-step explanation:

255

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I really need help with this problem, I don't know how to do it. Please help if you can.

Stels [109]

Answer:

see below

Step-by-step explanation:

2/3 +y =1/4

Subtract 2/3 from each side

2/3-2/3 +y =1/4-2/3

y = 1/4 -2/3

Get a common denominator

y = 1/4 (3/3) - 2/3 *4/4

= 3/12 - 8/12

=-5/12

or if

2/(y+3) = 1/4

Using cross products

y+3 = 2*4

y+3 = 8

y =8-3

y = 5

5 0

3 years ago

Read 2 more answers

Let V be the volume of the solid obtained by rotating about the y-axis the region bounded y = sqrt(25x) and y = x^2/25. Find V b

Westkost [7]

Explanation:

Let $f(x) = \sqrt{25x}$ and $g(x) = \frac{x^2}{25}$ . The differential volume dV of the cylindrical shells is given by

$dV = 2\pi x[f(x) - g(x)]dx$

Integrating this expression, we get

$\displaystyle V = 2\pi\int{x[f(x) - g(x)]}dx$

To determine the limits of integration, we equate the two functions to find their solutions and thus the limits:

$\sqrt{25x} = \dfrac{x^2}{25}$

We can clearly see that x = 0 is one of the solutions. For the other solution/limit, let's solve for x by first taking the square of the equation above:

$25x = \dfrac{x^4}{(25)^2} \Rightarrow \dfrac{x^3}{(25)^3} = 1$

$x^3 =(25)^3 \Rightarrow x = \pm25$

Since we are rotating the functions around the y-axis, we are going to use the x = 25 solution as one of the limits. So the expression for the volume of revolution around the y-axis is

$\displaystyle V = 2\pi\int_0^{25}{x\left(\sqrt{25x} - \frac{x^2}{25}\right)}dx$