Answer:
The relationship in this equation is linear, but not proportional. If it was proportional, then replacing x with nx should give ny as the answer. Example:
y = 3x
Replace x with 2x.
y' = 3(2x) = 2(3x) = 2y
y' = 2y
This is proportional. But if you replace x with 2x in
y = 3x + 5,
you will not get 2y for y'. This case is not proportiona
Y - y₁ = m(x - x₁)
y - 4 = -2(x - 6)
y - 4 = -2(x) + 2(6)
y - 4 = -2x + 12
+ 4 + 4
y = -2x + 16
The answer is D, (6, 4).
Answer:
15:25
Step-by-step explanation:
15 correct from 25 total
Hmm, the 2nd derivitve is good for finding concavity
let's find the max and min points
that is where the first derivitive is equal to 0
remember the difference quotient
so
f'(x)=(x^2-2x)/(x^2-2x+1)
find where it equals 0
set numerator equal to 0
0=x^2-2x
0=x(x-2)
0=x
0=x-2
2=x
so at 0 and 2 are the min and max
find if the signs go from negative to positive (min) or from positive to negative (max) at those points
f'(-1)>0
f'(1.5)<0
f'(3)>0
so at x=0, the sign go from positive to negative (local maximum)
at x=2, the sign go from negative to positive (local minimum)
we can take the 2nd derivitive to see the inflection points
f''(x)=2/((x-1)^3)
where does it equal 0?
it doesn't
so no inflection point
but, we can test it at x=0 and x=2
at x=0, we get f''(0)<0 so it is concave down. that means that x=0 being a max makes sense
at x=2, we get f''(2)>0 so it is concave up. that means that x=2 being a max make sense
local max is at x=0 (the point (0,0))
local min is at x=2 (the point (2,4))
