What is the area of a rectangle that is 3 1/2 x 6 1/2?

Monthly spending : $46,$62,$63,$57,$50$42$56$40 its median, mode and range

ozzi

Mean = $52
median = $53
no mode
range = 63 - 40 = $23

6 0

3 years ago

A quality control worker checked that 3 out of 40 TVs are defective(do not work).

gregori [183]

Answer:

600

Step-by-step explanation:

Divide 8000 by 40 then multiply by 3

4 0

3 years ago

Read 2 more answers

Solve the following system of equations by graphing.

never [62]

Answer:

(x,y)=(3,1)

Step-by-step explanation:

8 0

3 years ago

G Blue Ribbon taxis offers shuttle service to the nearest airport. You look up the online reviews for Blue Ribbon taxis and find

Dominik [7]

Answer:

This is a biased sampling method for obtaining customer opinions because those who take the time to write an online review are likely to do so because they are upset with the service they received.
The direction of the bias is likely to overestimate the proportion of customers who have a negative opinion on the service.

Step-by-step explanation:

1) There are groups which are not represented in the survey like those who don't use web. And also those who take the time to write an online review are likely to do so because they are upset with the service they received.

2) Those who had negative experience are more likely to write a review than those who had not.

4 0

3 years ago

Two brands of AAA batteries are tested in order to compare their voltage. The data summary can be found below. Find the 93% conf

kobusy [5.1K]

Answer:

$(\bar X_1 -\bar X_2) \pm z_{\alpha/2} \sqrt{\frac{s^2_1}{n_1}+\frac{s^2_}{n_2}}$

And replacing we got:

$(9.2 -8.8) - 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.2903$

$(9.2 -8.8) + 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.5097$

And the confidence interval for the difference of means would be given by:

$0.2903 \leq \mu_1 -\mu_2 \leq 0.5097$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

We have the following data given:

$\bar X_1 = 9.2 , \bar X_2 = 8.8, \sigma_1= 0.3, n_1 = 27, \sigma_2 = 0.1, n_2 = 30$

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 93% of confidence, our significance level would be given by $\alpha=1-0.93=0.07$ and $\alpha/2 =0.035$ . And the critical value would be given by:

$z_{\alpha/2}=-1.811, z_{1-\alpha/2}=1.811$

The confidence interval is given by:

$(\bar X_1 -\bar X_2) \pm z_{\alpha/2} \sqrt{\frac{s^2_1}{n_1}+\frac{s^2_}{n_2}}$

And replacing we got:

$(9.2 -8.8) - 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.2903$

$(9.2 -8.8) + 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.5097$

And the confidence interval for the difference of means would be given by:

$0.2903 \leq \mu_1 -\mu_2 \leq 0.5097$

4 0

3 years ago