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3 years ago

Solve the following system of equations: x − 2y = 14 x + 3y = 9

Mathematics

2 answers:

zheka24 [161]3 years ago

8 0

Answer:

(12, - 1)

Step-by-step explanation:

x - 2y = 14 ......... (1)

x + 3y = 9 ......... (2)

(2) - (1)

(x - x) + (3y - ( - 2y)) = 9 - 14

5y = - 5 ⇒ y = - 1

x + 3( - 1) = 9 ⇒ x = 12

(12, - 1)

nikdorinn [45]3 years ago

6 0

(12,-1) or x=12 and y=-1

EXPLANATION:
you set both equations equal to each other by subtracting the sum and adding it to the equation. once you set them equal to eachother (x-2y-14=x+3y-9)
you can solve by moving everything to one side by subtracting. once you get it all to one side you can start adding common numbers and variables and solve

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What is the percent for .166

Westkost [7]

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.166 x 100=16.6
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8 0

3 years ago

Use a graphing calculator to graph the function and its parent function. Then describe the transformations, f(x)=(x+3)+1/4

nlexa [21]

Most of the graphing resources used shows that the graph is translated up by 3.25 (3 + 1/4). If you add the 3 and the 1/4, you get the equation of a line:

f(x) = x + 3.25,

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The graphs are below. The red line represents f(x) = x, and the green line represents (x+3)+1/4. Hope this helps!

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3 years ago

Solve for the missing length and the other two angles in the triangle below

Klio2033 [76]

Answer:

AC = 3.72 units

Angles:

A = 132.6°

C = 27.4°

Step-by-step explanation:

AC² = 5² + 8² - 2(5)(8)cos(20)

AC² = 13.82459034

AC = 3.718143399

3.718143399/sin20 = 8/sinA

sinA = 0.7358944647

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A = 132.6171487

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5 0

3 years ago

Which of the following points are more than 5 units from the point P(−2, −2)? Select all that apply. A A (2, 1) B B (4, −1) C C

netineya [11]

The distance between any 2 points P(a,b) and Q(c,d) in the coordinate plane, is given by the formula:

 $|PQ|= \sqrt{ (a-c)^{2} + (b-d)^{2}}$

Using this formula we calculate the distances |PA|, |PB|, |PC|, |PD| and |PE| and compare to 5.

$|PA|= \sqrt{ (-2-2)^{2} + (-2-1)^{2}}= \sqrt{16+9}= \sqrt{25}=5$

$|PB|= \sqrt{ (-2-4)^{2} + (-2+1)^{2}}= \sqrt{36+1}= \sqrt{37} \approx 6$

$|PC|= \sqrt{ (-2-2)^{2} + (-2+3)^{2}}= \sqrt{16+1}= \sqrt{17}\approx4$

$|PD|= \sqrt{ (-2+6)^{2} + (-2+6)^{2}}= \sqrt{16+16}= \sqrt{32}\ \textgreater \ \sqrt{25}=5$

$|PE|= \sqrt{ (-2+5)^{2} + (-2-1)^{2}}= \sqrt{9+9}= \sqrt{16}=4$

Answer: B and D

3 0

3 years ago

Find the area of a circle with radius, r = 5.99m. Give your answer rounded to 2 DP.

GalinKa [24]

Answer: 112.72

Step-by-step explanation: We know that the formula for area of a circle is pi*r^2. Now we plug in the values. pi*5.99^2. Next we get rid of the exponent. 5.99*5.99 = 35.8801. Now we have pi*35.8801. Now if you are gonna use actual pi for this your answer would be 112.72065857. Round it to 2 decimal points and you have 112.72 . If you do 35.8801*3.14=112.663514 -> Round this and you have 112.66. So any of them would actually work but I would stick with 112.72.

3 0

3 years ago