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Maurinko [17]
3 years ago
12

Solve the following system of equations: x − 2y = 14 x + 3y = 9

Mathematics
2 answers:
zheka24 [161]3 years ago
8 0

Answer:

<em>(12, - 1) </em>

Step-by-step explanation:

x - 2y = 14 ......... <em>(1)</em>

x + 3y = 9 ......... <em>(2)</em>

<em>(2) - (1)</em>

(x - x) + (3y - ( - 2y)) = 9 - 14

5y = - 5 ⇒ <u><em>y = - 1</em></u>

x + 3( - 1) = 9 ⇒ <u><em>x = 12</em></u>

<em>(12, - 1)</em>

nikdorinn [45]3 years ago
6 0
(12,-1) or x=12 and y=-1

EXPLANATION:
you set both equations equal to each other by subtracting the sum and adding it to the equation. once you set them equal to eachother (x-2y-14=x+3y-9)
you can solve by moving everything to one side by subtracting. once you get it all to one side you can start adding common numbers and variables and solve
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Wittaler [7]

(1) ∠ABC = 65°, ∠DBE = 65°, ∠CBE = 115°, ∠ABD = 115°

(2) ∠ABC = 62°, ∠DBE = 62°, ∠CBE = 118°, ∠ABD = 118°

Solution:

(1) In the given image ABC and DBE are vertical angles.

<u>Vertical angle theorem:</u>

If two angles are vertical then they are congruent.

⇒ ∠ABC = ∠DBE

⇒ 3x° + 38° = 5x° + 20°

Arrange like terms one side.

⇒ 38° – 20° = 5x° – 3x°

⇒ 18° = 2x°

⇒ x° = 9°

∠ABC = 3(9°) + 38° = 65°

∠DBE = 5(9°) + 20° = 65°

Adjacent angles in a straight line = 180°

⇒ ∠ABC + ∠CBE = 180°

⇒ 65° + ∠CBE = 180°

⇒ ∠CBE = 115°

∠ABD and ∠CBE are vertical angles.

∠ABD = 115°

(2) In the given image ABC and DBE are vertical angles.

⇒ ∠ABC = ∠DBE

⇒ 4x° + 2° = 5x° – 13°

Arrange like terms one side.

⇒ 13° + 2° = 5x° – 4x°

⇒ 15° = x°

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∠DBE = 5(15°) – 13° = 62°

Adjacent angles in a straight line = 180°

⇒ ∠ABC + ∠CBE = 180°

⇒ 62° + ∠CBE = 180°

⇒ ∠CBE = 118°

∠ABD and ∠CBE are vertical angles.

∠ABD = 118°

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