Answer:
The space available will vary between 800 GB (100%) and 400 GB (50%) of the total disks, depending on the RAID level.
The OS will handle the RAID as a single disk.
Explanation:
Each RAID level implements parity and redundancy in a different way, so the amount of disks used for this extra information will reduce the space available for actual storage.
Usual RAID levels are:
<u>RAID 0:</u> does not implement any redundancy or parity, so you will have available 100% of the total storage: 8 x 100 GB = 800 GB
<u>RAID 1:</u> Duplicates all the information in one disk to a second disk. Space is reduced in half: 400 GB
<u>RAID 5:</u> Uses the equivalent of 1 disk of parity data distributed evenly on each disk, meaning the space available is 
of the total disks: 
of 800 GB = 700 GB
Writting and reading the information on a RAID storage is handled by a raid controller, either implemented in hardware or software. The OS will "see" a single disk and will read or write information as usual.
False if the roots modify it’s capable of it’s attributed set
Answer:
the technologynwhich is used in our locality os calleg local technology
ex. biogas farm , modern methods of 1transport etc
As specified in RFC5735, this is an address from the "link local" block. It is assigned to a network interface as a temporary address, for instance if no static address is configured and the DHCP server is not found.
If you boot your PC without a network cable, you'll probably end up with a 169.254.*.* address.
Answer:
#include <iostream>
using namespace std;
class Digits
{
public:
int num;
int read() //method to read num from user
{
cout<<"Enter number(>0)\n";
cin>>num;
return num;
}
int digit_count(int num) //method to count number of digits of num
{
int count=0;
while(num>0) //loop till num>0
{
num/=10;
count++; //counter which counts number of digits
}
return count;
}
int countDigits(int num) //method to return remainder
{
int c=digit_count(num); //calls method inside method
return num%c;
}
};
int main()
{
Digits d; //object of class Digits is created
int number=d.read(); //num is read from user
cout<<"\nRemainder is : "<<d.countDigits(number); //used to find remainder
return 0;
}
Output :
Enter number(>0)
343
Remainder is : 1
Explanation:
As program is missing to find errors , a logically write program is written to find the remainder when a number is divided by its number of digits. A class Digits is constructed which has public variable num and methods read(), digit_count(), countDigits().
- read() - This method reads value of num from the user and return num.
- digit_count() - This method takes a integer as parameter and counts the number of digits of a number passed as argument. while loop is used to increement the counter until num<0. This returns the value of count.
- countDigits() - This method takes a integer as a parameter and returns remainder when the argument is divided by number of digits of argument. Number of digits is calculated by using method digit_count().
At last in main method , object of Digits class is created and its methods are used to find the output.
