The responsibility for failures was deflected away from the automated parts of the system (and the humans, such as engineers, whose control is mediated through this automation) and placed on the immediate human operators, who possessed only limited knowledge and control.
Answer:
this is the method of processing wood
Answer:
def sum_1k(M):
s = 0
for k in range(1, M+1):
s = s + 1.0/k
return s
def test_sum_1k():
expected_value = 1.0+1.0/2+1.0/3
computed_value = sum_1k(3)
if expected_value == computed_value:
print("Test is successful")
else:
print("Test is NOT successful")
test_sum_1k()
Explanation:
It seems the hidden part is a summation (sigma) notation that goes from 1 to M with 1/k.
- Inside the <em>sum_1k(M)</em>, iterate from 1 to M and calculate-return the sum of the expression.
- Inside the <em>test_sum_1k(),</em> calculate the <em>expected_value,</em> refers to the value that is calculated by hand and <em>computed_value,</em> refers to the value that is the result of the <em>sum_1k(3). </em>Then, compare the values and print the appropriate message
- Call the <em>test_sum_1k()</em> to see the result
Black or blue pen would be appropriate.
Answer:
// Program is written in C++ Programming Language
// Comments are used for explanatory purpose
// Program starts here
#include<iostream>
using namespace std;
int main()
{
// Declare integer variable n which serves as the quotient.
int n;
// Prompt to enter any number
cout<<"Enter any integer number: ";
cin>>n;
// Check for divisors using the iteration below
for(int I = 1; I<= n; I++)
{
// Check if current digit is a valid divisor
if(n%I == 0)
{
// Print all divisors
cout<<I<<" ";
}
}
return 0;
}