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3 years ago

8

Add using a number line. +(-11)

1 answer:

Nikolay [14]3 years ago

4 0

Answer:

-11 is the anwer.

As it is present in left side, so -11 will be in left part of number line.

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It will most likely just rain on Monday

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How to write 3805076 in words

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Thirty eight million fifty thousand and seventy six

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What is the name given for genetic changes in living things over time?

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3 years ago

The hundreds digit and the ones digit of a three digit number are the same. The sum of its tree digits are 16. If the tens digit

tensa zangetsu [6.8K]

<h2>727</h2>

Step-by-step explanation:

Let us denote the three digit number by $abc$ , where $a$ is the hundreds digit, $b$ is the tens digit and $c$ is the ones digit.

Hundreds digit = $a$ = Ones digit = $c$

Sum of digits = $a+b+c=16$

So, $2c+b=16$

On exchanging tens and ones digit, value increases by 45. So $acb$ is 45 greater than $abc$ .

$acb-abc=45$

$100a+10c+b-100a-10b-c=45\\9c-9b=45\\c-b=5$

$2c+b=16,c-b=5\\3c=21\\c=7=a\\b=2$

∴ Required number is 727

7 0

3 years ago

Maths functions question

yarga [219]

Answer:

a) OA = 1 unit

b) OB = 3 units

c) AB = √10 units

Step-by-step explanation:

<u>Given function</u>:

$g(x)=2^x$

<h3><u>Part (a)</u></h3>

Point A is the y-intercept of the exponential curve (so when x = 0).

To find the y-value of Point A, substitute x = 0 into the function:

$\implies g(0)=2^0=1$

Therefore, A (0, 1) so OA = 1 unit.

<h3><u>Part (b)</u></h3>

If BC = 8 units then the y-value of Point C is 8.

The find the x-value of Point C, set the function to 8 and solve for x:

$\begin{aligned}f(x) & = 8 \\\implies 2^x & = 8\\2^x & = 2^3\\\implies x &= 3\end{aligned}$

Therefore, C (3, 8) so Point B is (3, 0). Therefore, OB = 3 units.

<h3><u>Part (c)</u></h3>

From parts (a) and (b):

A = (0, 1)
B = (3, 0)

To find the length of AB, use the distance between two points formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$\textsf{where }(x_1,y_1) \textsf{ and }(x_2,y_2)\:\textsf{are the two points.}$

Therefore:

$\implies \sf AB=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}$

$\implies \sf AB=\sqrt{(3-0)^2+(0-1)^2}$

$\implies \sf AB=\sqrt{(3)^2+(-1)^2}$

$\implies \sf AB=\sqrt{9+1}$

$\implies \sf AB=\sqrt{10}\:\:units$

5 0

2 years ago