What is the answer? 236,272 round to the nearest ten thousand

Mathematics

1 answer:

mr_godi [17]3 years ago

8 0

The answer is just 236,000 I hope it helps and is right

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The perimeter of a rectangle is 56 inches. The length is 4 more than twice the width. Write and solve a system to determine the

Marianna [84]

Width: x
length: x + 4
Equation: 2(x + x + 4) = 56
2(2x + 4) = 56
4x + 8 = 56
4x = 48, x = 12
Width = 12, 12 + 4 = length
Solution: the length is 16 inch

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2 years ago

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A trapezoid has an area of 294 square yards. Its height is 14 yards and the length of one base is 30 yards. Find the length of t

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3 years ago

A=bh; A=48, b=12 what is h equal?

OleMash [197]

1. Plug in numbers
•48=12h
2. Divide 48 by 12
•48/12=12h/12
3. 12/12 cancels out, and 48/12=4

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3 years ago

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Help I am very bad at math I need answers by tomorrow if you can help please do

d1i1m1o1n [39]

Answer:

Step-by-step explanation:

(a - b)(a +b) = a² - b²

1 - Sin² A = Cos² A

$LHS = \frac{1}{1- Sin A} + \frac{1}{1 + Sin A}\\\\= \frac{1*(1 + Sin A)}{(1- Sin A)(1 + Sin A)} + \frac{1*(1- Sin A)}{(1 + Sin A)(1- Sin A)}\\\\= \frac{1 + Sin A+ 1 - Sin A}{1^{2}- Sin^{2} A}\\\\= \frac{2}{1 - Sin^{2} A}\\\\= \frac{2}{Cos^{2} A}\\\\= 2 Sec^{2} A$

2) Sec² A - Tan² A = 1

$LHS = \frac{1}{Sec A - Tan A}\\\\=\frac{1*(Sec A + Tan A)}{(Sec A - Tan A)(Sec A + Tan A)}\\\\=\frac{Sec A + Tan A}{Sec^{2} A - Tan^{2} A}\\\\=\frac{Sec A + Tan A }{1}\\\\= Sec A + Tan A = RHS\\\\\\$

3) LHS = Cosec² A + Cot² A

= Cosec² A + Cosec² A - 1

= 2Cosec² A - 1 = RHS

$4) LHS = \frac{Sec A}{Cos A}- \frac{Tan A}{Cot A}\\\\ = Sec A*\frac{1}{Cos A}-Tan A*\frac{1}{Cot A}\\\\ = Sec A * Sec A - Tan A * Tan A\\\\= Sec^{2} A - Tan^{2} A \\\\= 1$