Answer:
(3,16)
Step-by-step explanation:
The degrees of freedom of the critical value F are (k-1,n-k).
We are given that there are four sample group, so,
k=4.
Also, we are given that the each four groups contains five observations, so,
n=4*5
n=20
The critical value F has degree of freedom
(k-1,n-k)
(4-1,20-4)
(3,16).
Thus, the degrees of freedom for the critical value of F are (3,16).
4,6,8 because 4 times 2 is 8 and 6 times 1 equals 6 and 1 times 4 equals 4
Well
It is in the form of a/b + b/a = (a sqr + b sqr)ab
Substitute
(Sin sqr theta + cos sqr theta) +2 cos theta + 1. 2 + 2cos theta
———————————————————————— = ————————-
Sin theta(1+cos theta). Sin theta (1 + cos theta)
2(1+ cos theta)/sin theta(1 + cos theta). {1 + cos theta cancelled}
2/sin theta. Hope it helps :}
