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4 years ago

Can someone plss help me

Mathematics

1 answer:

puteri [66]4 years ago

7 0

0/3 is the same thing as 0, so write those nxt to each other. Then 1/3, 2/3. Lastly 3/3 is the same as 1, so write those nxt to each other.

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I used a calculator and have solved it without. I didn't get any of these answers. HELP

Andreas93 [3]

Answer:

-9 + 7√5.

Step-by-step explanation:

(3 - √5)(2 + 3√5)

= 3(2 + 3√5) - √5(2 + 3√5))

= 6 + 9√5 - 2√5 - 15

= -9 + 7√5.

6 0

3 years ago

Consider the system of differential equations dxdt=−4ydydt=−4x. Convert this system to a second order differential equation in y

koban [17]

$\dfrac{\mathrm dy}{\mathrm dt}=-4x\implies x=-\dfrac14\dfrac{\mathrm dy}{\mathrm dt}\implies\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac14\dfrac{\mathrm d^2y}{\mathrm dt^2}$

Substituting this into the other ODE gives

$-\dfrac14\dfrac{\mathrm d^2y}{\mathrm dt^2}=-4y\implies y''-16y=0$

Since $x(t)=-\dfrac14y'(t)$ , it follows that $x(0)=-\dfrac14y'(0)=4\implies y'(0)=-16$ . The ODE in $y$ has characteristic equation

$r^2-16=0$

with roots $r=\pm4$ , admitting the characteristic solution

$y_c=C_1e^{4t}+C_2e^{-4t}$

From the initial conditions we get

$y(0)=5\implies 5=C_1+C_2$

$y'(0)=16\implies-16=4C_1-4C_2$

$\implies C_1=\dfrac12,C_2=\dfrac92$

So we have

$\boxed{y(t)=\dfrac12e^{4t}+\dfrac92e^{-4t}}$

Take the derivative and multiply it by -1/4 to get the solution for $x(t)$ :

$-\dfrac14y'(t)=\boxed{x(t)=-\dfrac12e^{4t}+\dfrac92e^{-4t}}$

7 0

3 years ago

HELP I REALLY NEED AN ANSWER WILL GIVE BRAINLIEST IF I CANNNNN

dmitriy555 [2]

Answer:

Step-by-step explanation:

6 0

3 years ago

What is the slope of a line perpendicular to the given line plz

stiks02 [169]

Answer:

it should be the negative repirocal of -2 so 1/2

6 0

3 years ago

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Rewrite 5 3/7 as an improper fraction.

bija089 [108]

The answer should be 38/7

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3 years ago

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