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Amanda [17]
3 years ago
11

20 - k/15 = 17 What is k?

Mathematics
2 answers:
tester [92]3 years ago
6 0
20 - k/15 = 17
20 - 17 = k/15
     3 = k/15
       k = 45
diamong [38]3 years ago
4 0
K=45

20-k/15=17
-k/15=-3
-k=-45
k=45

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(X^2+x-6)(2x^2+4x) factor completely
MissTica

Answer:

2x\left(x-2\right)\left(x+3\right)\left(x+2\right)

Step-by-step explanation:

Lets go ahead and take a step by step approach to solving your problem.

First we must start by factoring x^2+x-6.

To do this, we must break the expression into groups! Although I will also provide a definition to help you understand! For ax^2+bx+c we need to find u, v > u\cdot \:v=a\cdot \:c and u+v=b which we will group into \left(ax^2+ux\right)+\left(vx+c\right).

The values we have are...a=1,\:b=1,\:c=-6 and u\cdot v=-6,\:u+v=1.

Now we need the factors of 6 which are 1, 2, 3 and 6. We also need the negative factors which you get simply by multiplying the positives by -1 or just reversing them.

Now we need to check for every two factors if u + v = 1.

\mathrm{Check}\:u=1,\:v=-6: \:u\cdot v=-6,\:u+v=-5 \Rightarrow  \mathrm{False}

\mathrm{Check}\:u=2,\:v=-3: \:u\cdot v=-6,\:u+v=-1 \Rightarrow  \mathrm{False}

\mathrm{Check}\:u=3,\:v=-2: \:u\cdot v=-6,\:u+v=1 \Rightarrow  \mathrm{True}

\mathrm{Check}\:u=6,\:v=-1: \:u\cdot v=-6,\:u+v=5 \Rightarrow  \mathrm{False}

Therefore u=3,\:v=-2.

Now we want to \mathrm{Group\:into\:}\left(ax^2+ux\right)+\left(vx+c\right). Which is \left(x^2-2x\right)+\left(3x-6\right).

Now we must factor x from x^2-2x.

Lets apply the exponent rule of a^{b+c}=a^ba^c which means x^2=xx.

Therefore we now have xx - 2x. Lets factor out the common term of x to get x(x - 2).

Now factor 3 out of 3x-6.

Rewrite 6 as 3 * 2. 3x-3\cdot \:2.

Now factor out the common term of 3 > 3\left(x-2\right).

x\left(x-2\right)+3\left(x-2\right) > Factor out the common term of x - 2 > \left(x-2\right)\left(x+3\right).

Now lets factor 2x^2+4x.

Apply the previous exponent rule of a^{b+c}=a^ba^c > x^2=xx > 2xx+4x.

Now rewrite 4 as 2 * 2 > 2xx+2\cdot \:2x.

Now factor out the common term of 2x to get 2x(x + 2).

Combine it all and we get 2x\left(x-2\right)\left(x+3\right)\left(x+2\right).

Hope this helps!

7 0
3 years ago
Help with this question to
Maslowich
If you're looking for which of these has the best price, the answer would be the first one, since it is the cheapest out of the 4. If that's not the right way to solve it, let me know!
6 0
3 years ago
2 + 2 ez badge yeah ok now what do i do
Marrrta [24]

Answer:

4

2 + 2 = 4

took me longer then I expected

6 0
3 years ago
What is the sum of the polynomials?<br> (7x^3– 4x^2) + (2x^3 +3x)
DaniilM [7]

Answer:

sum of the polynomials is 9 x^{3} - 4 x^{2} +3x

Step-by-step explanation:

Given polynomial is (7 x^3– 4 x^2) + (2 x^3 +3 x)

adding x^3 terms, now we get

(7+2)x^3-4 x^2+3 x

9 x^{3} - 4 x^2 +3 x

Therefore the sum of given polynomial is

9 x^3-4 x^2+3 x

5 0
3 years ago
Which of the following points lie in the solution set to the following system of inequalities?
laiz [17]

Answer:

B. (5,-2)

Step-by-step explanation:

Plug in X and Y, verify accuracy

7 0
4 years ago
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