Answer is 2nd option
B. WYZ = WZX = ZYX
When
, you're left with
When
or
, you're left with
Adding the two equations together gives
, or
. Subtracting them gives
,
.
Now, you have
By just examining the leading and lagging (first and last) terms that would be obtained by expanding the right side, and matching these with the terms on the left side, you would see that
and
. These alone tell you that you must have
and
.
So the partial fraction decomposition is
1 / 10 of 0.08
1 / 10 * 0.08
0.08 / 10
0.008 Ans
Answer:
b+6
Problem:
If the average of b and c is 8, and d=3b-4, what is the average of c and d in terms of b?
Step-by-step explanation:
We are given (b+c)/2=8 and d=3b-4.
We are asked to find (c+d)/2 in terms of variable, b.
We need to first solve (b+c)/2=8 for c.
Multiply both sides by 2: b+c=16.
Subtract b on both sides: c=16-b
Now let's plug in c=16-b and d=3b-4 into (c+d)/2:
([16-b]+[3b-4])/2
Combine like terms:
(12+2b)/2
Divide top and bottom by 2:
(6+1b)/1
Multiplicative identity property applied:
(6+b)/1
Anything divided by 1 is that anything:
(6+b)
6+b
b+6
