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KiRa [710]
3 years ago
14

Solve for x in the equation x^2-14+31=63

Mathematics
1 answer:
Bingel [31]3 years ago
3 0
To solve for a variable, you need to get it (x) by itself.

x² - 14 + 31 = 63   Add 31 to -14
x² + 17 = 63   Subtract 17 from both sides of the equation
x² = 46   Square root both sides
x = \pm \sqrt{46}

Check your work by plugging in \sqrt{46} for x and then - \sqrt{46}.

\sqrt{46}² - 14 + 31 = 63   Square \sqrt{46}
46 - 14 + 31 = 63   Subtract 14 from 46
32 + 31 = 63   Add
63 = 63

- \sqrt{46}² - 14 + 31 = 63   Square - \sqrt{46}
46 - 14  + 31 = 63   Subtract 14 from 46
32 + 31 = 63   Add
63 = 63

So, x is \sqrt{46} and - \sqrt{46} .
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Answer:

  1/6

Step-by-step explanation:

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Q14
posledela

Answer:

42.6cm

Step-by-step explanation:

The sum total of all the sides of the shape is the perimeter of the shape. Hence;

Perimeter = x+3 + 4 + x+9 + 2x+5

Perimeter = 4x + 21

Given

Area of the figure = 75cm^2

Area = (x+3)(2x+5) + (2x+1)(6)

75 = 2x²+5x+6x+15+12x+6

75 =  2x²+23x+21

2x²+23x+21-75 = 0

2x²+23x-54 = 0

x = -23±√23²-4(2)(-75)/4

x = -23±√529+600/4

x = -12±√1129/4

x = -12+33.6/4

x = 21.6/4

x = 5.4

Recall that;

Perimeter = 4x+21

Perimeter = 4(5.4) + 21

Perimeter = 21.6+21

Perimeter = 42.6cm

Hence the perimeter is 42.6cm

8 0
3 years ago
An isosceles triangle with equal sides of 5 inches and a base of 6 inches is inscribed in a circle. What is the radius, in inche
nikklg [1K]
Wow this is a doozy! First you have to figure out what is it you are looking for? If you make a dot in the center of the triangle (which is also the center of the circle) and draw a line from the center to one of the vertices of the triangle you have the radius of the triangle and also of the circle. If you draw all 3 radii from the triangle's center to its vertices, you see you have created 3 triangles within that one triangle.  The trick here is to figure out what your triangle measures are as far as angles go.  If we take the interior measures of those 3 triangles, we get that each one has a measure of 120 (360/3=120). So that's one of your angles, the one across from the side measuring 6. Because of the Isosceles Triangle theorem, we know that the 2 base angles have the same measure because the sides are the same. Subtracting 120 from 180 gives you 60 which, divided in half, makes each of those remaining angles measure 30 degrees. So if we extract that one triangle from the big one, we have a triangle with angles that measure 30-30-120, with the base measuring 6 and each of the other sides measuring 5. If we then split that triangle into 2 right triangles, we have one right triangle with measures 30-60-90. Dropping that altitude to create 2 right triangles not only split the 120 degree angle at the top in half, it also split the base side of 6 in half. So our right triangle has a base of 3 and we are looking for the hypotenuse of that right triangle.  WE have to use right triangle trig for that. Since we have the top angle of 60 and the base of 3, we can use sin60=3/x.  Solving for x we have x=3/sin60 which gives us an x value of 3.5 inches rounded from 3.464. I'm not sure what you mean by a mixed number unless you mean a decimal, but that's the radius of that circle.
6 0
3 years ago
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