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inysia [295]
3 years ago
13

What is the mean,mode,median,and range of 5,5,5,6,6,6,7,7,7,7,7​

Mathematics
2 answers:
g100num [7]3 years ago
7 0

Answer:

median=6, range=2 mean=61 mode=7

the median is the middle which is 6

The range is the lowest-biggest number which would be 2

mean=average

mode is the one that appears most

andreev551 [17]3 years ago
3 0

Answer:

68 / 11 = mean

7 = mode

6 = median

2 = range

Step-by-step explanation:

Mean means the average

Mode means the most common

Median means the middle

<u>Step 1:  Find the mean by adding all the values then dividing by the amount of values</u>

5 + 5 + 5 + 6 + 6 + 6 + 7 + 7 + 7 + 7 + 7​ = 68

68 / 11 = mean

<u>Step 2:  Find the mode which is the most common</u>

5, 5, 5, 6, 6, 6, 7, 7, 7, 7, 7​

5 is repeated 3 times, 6 is repeated 3 times, 7 is repeated 5 times

7 = mode

<u>Step 3:  Find the median which is the middle</u>

<u>5, 5, 5, 6, 6</u>, 6, <u>7, 7, 7, 7, 7​</u>

6 = median because it is in the middle

<u>Step 4:  Find the range which is the difference the highest and lowest number</u>

7 - 5 = 2

2 = Range

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3 years ago
Multiple choice. Use the Law of Sines to find the missing angle of the triangle. Find m angle C to the nearest tenth if c = 111
nalin [4]

Answer:

Both A and B are possible.

Step-by-step explanation:

It's both!

This is a might tricky. First you have to find the altitude. You have to determine if this is a real triangle.

Sin(22) = opposite / hypotenuse. The hypotenuse = 111. The angle is 22

opposite = hypotenuse * sin(22)

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opposite = 41.58  and this is the altitude.

What have you learned?

Since 42 is larger than 41.58 you have 2 solutions to the triangle. One of the angles is acute, and the other one is obtuse. They are supplementary angles.

Sin(C) / c = Sin(A) / a

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Sin(C) = 111*sin(22)/ 42

Sin(C) = .99003

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7 0
3 years ago
If there was a total of 30 computers and the computer lab is removing 3 broken computers and adding 13 wireless devices, about w
Liula [17]

32.5 % of lab are wireless devices

<em><u>Solution:</u></em>

Given that there was a total of 30 computers and the computer lab is removing 3 broken computers and adding 13 wireless devices

Now we can first find out total number of computers and devices in lab

total number of computers and devices in lab = 30 computers - 3 + 13 wireless devices

total number of computers and devices in lab = 30 - 3 + 13 = 40

So there are 40 computers and wireless devices in lab

<em><u>To find: what percent of the lab are wireless devices</u></em>

So we have to find what percent of 40 is 13

Let "a" be the required percent

a % of 40 = 13

\frac{a}{100} \times 40 = 13\\\\a = \frac{13 \times 100}{40}\\\\a = 32.5

32.5 % of of lab are wireless devices

6 0
3 years ago
Im confused right now. What equasion is represented by the area model? Format as 2x2
algol [13]

40x30=120x5=600x6=3600

Awnser:3600

8 0
3 years ago
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