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emmasim [6.3K]
3 years ago
9

How do I solve the problem

Mathematics
1 answer:
Grace [21]3 years ago
6 0
Solution 1: 5x + 2y = 3  

Solution 2: 3x - 2y = 5

Graphic Organizer: 2(y) + 5(x) = 3
-2(y) + 3(x) = 5

The value of 'x' in solution 2

3(x) = 2(y) + 5
x = 2(y)÷ 3 + 5÷3

The value of 'y' in solution 1

5(2(y))÷3+5÷3 + 2(y) = 3  
16(y)÷3 = -16÷3  
16(y) = -16

y-intercept ➡ -1

x-intercept in both of The solutions!
(2÷ 3)(-1)+5÷ 3 = 1 

x-intercept : 1
y-intercept : -1

Your answer would have to be

(1, -1)
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Which is greater 25% of 16 or 20% of 25
zhannawk [14.2K]

Answer:

20% of 25 is greater

Step-by-step explanation:

25% of 16 = 4

20% of 25 = 5

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good morning fellow brainsters please help me i’m tired and i just drank a four loko... can’t think. will give 15 points
borishaifa [10]

Answer:

7. x=3

8. l=11cm and w=7 cm

9. x-5\ge12

10. \frac{x}{3}\le15

Step-by-step explanation:

Question 7.

The given expression is:

12-3(2x+1)=7x-3(7+x)

Expand the parenthesis using the distributive property:

12-6x-3=7x-21-3x

Group similar terms:

-6x-7x+3x=-21+3-12

Simplify

-10x=-30

Divide both sides by -10

x=3

Question 8:

Let the width of the rectangle be; w

The length of the rectangle is l=w+4

The perimeter is given as: P=2(l+w)

Given that the perimeter P=36, then:

36=2[(w+4)+w)]

\implies 36=2(2w+4)

Divide both sides by 2:

\implies 18=2w+4

Subtract 4 from both sides:

\implies 18-4=2w

\implies 14=2w

\implies w=7

The dimensions of the rectangle is: w=7 cm and l=7+4=11cm

Question 9

Let the number be x.

"5 fewer than the number" is written as x-5

"5 fewer than a number is at least 12" becomes

x-5\ge12

Question 10:

Let the number be x.

The quotient of a number and 3 is written as:

\frac{x}{3}

The quotient of a number and 3 is no more than 15 is written as;

\frac{x}{3}\le15

4 0
3 years ago
Can 10-12 be solved Answer Fast!!!!!!
zzz [600]

Answer:

10/------   5x+2y=14

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2 years ago
Suppose that a box contains 6 cameras and that 3 of them are defective. A sample of 2 cameras is selected at random. Define the
mezya [45]

Answer: 1/5, 1/2, 0.

Step-by-step explanation:

given data:

no of cameras = 6

no of cameras defective = 3

no of cameras selected = 2

Let p(t):=P(X=t)

p(2)=m/n,

m=binomial(3,2)=3!/2!= 3

n=binomial(6,2)=6!/2!/4! = 15

p(3)= 3/15

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p(1)=m/n,

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= 1/2

p(0)=m/n,

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7 0
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Lapatulllka [165]

Answer:

5 5/11 hours

Step-by-step explanation:

So, there is a trick to doing this.

You would first need to get their work rate into the same measurements.

That's why we will find out how much they each work in one hour.

Tommy does 1/12 of the work in one hour while Robert does 1/10.

Here we can add them both up to make 11/60.

They finish 11/60 of the work in one hour.

They finish the job in 5 5/11 hours.

8 0
3 years ago
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