Answer:
A) 0.335; B) 0.343; C) 0.599
Step-by-step explanation:
For part A,
To find the probability that the user has more than one infection per year, we can either add together the probabilities for 2, 3, 4 and 5; or we can add together the probabilities for 0 and 1 and subtract them from 1:
1-(P(X = 0)+P(X = 1))
= 1-(0.343+0.322) = 1-0.665 = 0.335
For part B,
The probability that the user has no infections per year is P(X = 0); this is 0.343.
For part C,
The probability that the user has between 1 and 3 infections (inclusive) per year is
P(1 ≤ X ≤ 3) = 0.322+0.201+0.076 = 0.599
34,235345 = thirty four million two hundred thirty
five thousand three hundred forty five
Answer:
38
Step-by-step explanation:
We are to solve for the expression;
2 + 3² × (5 - 1)
We should aply BODMAS here!
So starting with the brackets;
2 + 3² × 4
Then solving the multiplication part;
3² × 4 = 9 × 4 = 36
Finally adding the integers;
2 + 36 = 38
Answer:
1 4/25 - 3/5, or 29/25 - 3/5, or 
it doesn't really matter they all mean the same
Step-by-step explanation:
1 2/5m - 3/5(2/5m + 1)
multiply first
1 2/5m - 6/25m - 3/5
multiply 1 2/5 only so the denominator is 25 as we can't simplify 6/25, it's so we can add them together, we can't add 3/5 tho bc it's a different term so there's no need to multiply that.
1 10/25m - 6/25m - 3/5
add/subtract
1 4/25m - 3/5
297 because 289 rounds to 290 plus 7 is 297
