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The probability that the person pulls 1 blue M&M given that one is only allowed to pull 5 random M&M's per day will be 0.6450.
<h3>How to calculate probability?</h3>
From the information given, there are 1,023 M&M's in a bag and out of 1,023 M&M's, 132 M&M's are blue.
Therefore, the probability of getting a blue M&M will be:
= 132/1023
= 0.1290
Therefore, since the person is given the chance to pull 5 random M&M's per day, the probability will be:
= 0.1290 × 5
= 0.6450
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Answer:
The two sample t-test
Step-by-step explanation:
The appropriate test for thus is the two sample t test which is also known as the independent t test. This tests aims at determined whether there is a statistically significant difference between the means in two unrelated groups which in this context are a random sample with one type of preservative and another sample with another type of preservatives.
With this test, the researcher is able to compare the mean shelf lives of the bananas treated with the two different preservatives... The null hypothesis equalises the two means of the sample while the alternative does otherwise.
Answer:
nope
Step-by-step explanation:
2/5 + 1/2
4+5 / 10 • look for the LCD of 5 and 2
which is 10 then 5 goes 2
times into 10 the multiply by 2
= 4. Then 2 goes 5 times into
10 then multiply by 1 = 5.
Therefore the sum of 2/5 + 1/2 =9/10
