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cluponka [151]
3 years ago
7

The perimeter of a square is 36 inches. Find the length of a diagonal. Round your answer to the nearest tenth.

Mathematics
2 answers:
vovangra [49]3 years ago
5 0

Answer:

12.7

Step-by-step explanation:

The diagonal formula is x*sqrt(2) with x being one side length.

To find the side length divide the perimeter by 4.

That gives us 9.

Then, all you have to do is multiply that by the square root of 2 and then round.

Ad libitum [116K]3 years ago
4 0

Answer:

36/4 = 9

9 inch per side lol

9 rad 2 will be diagonal because of the 45 45 90 type triangle

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lesya [120]
1_ 0/4. ( if toss a coin twice, we won't have three results)

2_ 0/4

3_ 3/4

4_ 3/4

5 _ 1/4

6_ 1/4


good luck
4 0
3 years ago
Value of x in log5x = 4logx5 is
olchik [2.2K]
Log5 x=4 logx 5
Ln x/ln5=4(ln5 / ln x)                                 logx z=ln x / ln z
least common multiple=ln5 * ln x

ln²x=4ln²5
√(ln² x)=√(4 ln²5)
ln x=2ln 5
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3 years ago
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Anuta_ua [19.1K]
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8 0
3 years ago
Consider the function below. f(x) = ln(x4 + 27) (a) Find the interval of increase. (Enter your answer using interval notation.)
andrezito [222]

Answer:

a) The function is constantly increasing and is never decreasing

b) There is no local maximum or local minimum.

Step-by-step explanation:

To find the intervals of increasing and decreasing, we can start by finding the answers to part b, which is to find the local maximums and minimums. We do this by taking the derivatives of the equation.

f(x) = ln(x^4 + 27)

f'(x) = 1/(x^2 + 27)

Now we take the derivative and solve for zero to find the local max and mins.

f'(x) = 1/(x^2 + 27)

0 = 1/(x^2 + 27)

Since this function can never be equal to one, we know that there are no local maximums or minimums. This also lets us know that this function will constantly be increasing.

6 0
3 years ago
HELP ME PLZ ASAP 80 POINTS
KiRa [710]

Answer:

Slope:-1/3

y-intercept: (0,2)

x        y

0       2

6       0

Hope this helps a little

5 0
2 years ago
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