Answer:
Explained below.
Step-by-step explanation:
Consider the series is a set of first 6 natural numbers.
Sum of first <em>n</em> terms is:
![\text{Sum of n terms}=\frac{n(n+1)}{2}](https://tex.z-dn.net/?f=%5Ctext%7BSum%20of%20n%20terms%7D%3D%5Cfrac%7Bn%28n%2B1%29%7D%7B2%7D)
![\text{Sum of first 6 terms}=\frac{6(6+1)}{2}](https://tex.z-dn.net/?f=%5Ctext%7BSum%20of%20first%206%20terms%7D%3D%5Cfrac%7B6%286%2B1%29%7D%7B2%7D)
![=3\times7\\=21](https://tex.z-dn.net/?f=%3D3%5Ctimes7%5C%5C%3D21)
Consider the series is an arithmetic sequence.
Sum of first <em>n</em> terms is:
![S_{n}=\frac{n}{2} [2a+(n-1)d]](https://tex.z-dn.net/?f=S_%7Bn%7D%3D%5Cfrac%7Bn%7D%7B2%7D%20%5B2a%2B%28n-1%29d%5D)
Here<em>,</em>
<em>a</em> = first term
<em>d</em> = common difference
Consider the series is an geometric sequence.
Sum of first <em>n</em> terms is:
![S_{n}=\frac{a_{1}\cdot(1-r^{n})}{(1-r)}](https://tex.z-dn.net/?f=S_%7Bn%7D%3D%5Cfrac%7Ba_%7B1%7D%5Ccdot%281-r%5E%7Bn%7D%29%7D%7B%281-r%29%7D)
Here<em>,</em>
<em>a₁</em> = first term
<em>r</em> = common ratio
I think the correct answer is ( 2, 3 )
The answer would be 1/4 pounds((One and one quarter pounds)) I hope this helps :3