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AleksandrR [38]

3 years ago

12

I need help on Section 5- Topic 10 Algebra Nation, Algebra 1 Practice book. If anyone could give me answers to the questions, I

will be extremely thankful!

1 answer:

Pavlova-9 [17]3 years ago

5 0

Step-by-step explanation:

Just post a pic of the page

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Find the greatest common factor of 6w^3 and 5n^4

scZoUnD [109]

Hi there!

• Greatest Common Factor :-

GCF is th' greatest factor that divides two numbers.

To find the GCF of two numbers :-

→ List the prime factors of each number.
→ Multiply those factors both numbers have in common.

Accr'ding to the question :-

5n⁴ = 5 × n × n × n × n × 1
6w³ = 2 × 3 × w × w × w × 1

Greatest Common Factor [ 5n⁴, 6w³ ] = 1

~ Hope it helps!

7 0

3 years ago

What is the point-slope form of an equation passing through (0, -5) with a 5 points

Novay_Z [31]

Answer:

y=2x-5

Step-by-step explanation:

$y-y_{1}=m(x-x_{1})$

$x_{1}=0, y_{1}=-5\\$ , and m=2

$y-(-5)=2(x-0)$ , -(-5)-Two negatives make it positive, and you distribute the 2

$y+5=2x$ , you now subtract 5 to get y by itself to get your answer of

$y=2x-5$

*NOTE* (0,-5) is the y-intercept, so you could have used the linear equation of y=mx+b, m=2, and b(y-intercept)=-5

giving you y=2x-5

6 0

3 years ago

Enter a positive common factor other than 1 of the fractions numerator and denominator 55/80

g100num [7]

They both have 5 in common
if you were to reduce the fraction it would be 11/16 because
55 divided by 5 is 11 and 80 divided by 5 is 16

6 0

3 years ago

The revenue equation (in hundreds of millions of dollars) for barley production in a certain country is approximated by R(x) = 0

STatiana [176]

Answer:

The marginal-revenue equation is $R'(x)=0.1226x+1.1584$ .

The marginal revenue for the production of 200,000,000 bushels is $R'(x)=1.4036$ .

The marginal revenue for the production of 650,000,000 bushels is $R'(x)=9.1274$ .

Step-by-step explanation:

The derivative $R'(x)$ of the revenue function is called the marginal revenue function and is the rate of change of revenue with respect to the number of units sold.

We know the revenue function, $R(x) = 0.0613x^{2} +1.1584x+2.4813$ . Therefore, the marginal revenue function is

$R'(x)=\frac{d}{dx}R(x) = \frac{d}{dx}(0.0613x^{2} +1.1584x+2.4813)\\\\=\frac{d}{dx}\left(0.0613x^2\right)+\frac{d}{dx}\left(1.1584x\right)+\frac{d}{dx}\left(2.4813\right)\\\\R'(x)=0.1226x+1.1584$

To find the marginal revenue for the production of:

200,000,000 bushels we use x = 2, since x is in units of hundreds of million of dollars.

$R'(x)=0.1226\cdot \:2+1.1584\\\\R'(x)=0.2452+1.1584\\\\R'(x)=1.4036$

650,000,000 bushels we use x = 65, since x is in units of hundreds of million of dollars.

$R'(x)=0.1226\cdot \:65+1.1584\\\\R'(x)=7.969+1.1584\\\\R'(x)=9.1274$

3 0

3 years ago

What is 14/5 as a mixed number ?

mash [69]

2 and 4/5 is 14/5 as a mixed number.

4 0

4 years ago

Read 2 more answers