Directions: Consider a 2-kg bowling ball sits on top of a building that is 40 meters tall. It falls to the ground. Think about t
he amounts of potential and kinetic energy the bowling ball has:
What is the kinetic energy of the ball as it is half way through the fall?
What is the kinetic energy of the ball as it is half way through the fall?
1 answer:
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Answer:
The equivalent to one over five m − 20 is one over five (m − 100) ⇒ B
Step-by-step explanation:
Let us solve the question
∵ One over five means
∴ One over five m - 20 = m - 20
→ By using the distributive property, take one over five as a common factor
from both terms
∴ m - 20 =
-
→ Simplify the bracket
∵ m ÷
=
m × 5 = m
∵ 20 ÷ = 20 × 5 = 100
∴
-
=
(m - 100)
∴ m - 20 =
(m - 100)
The equivalent to one over five m − 20 is one over five (m − 100)