Directions: Consider a 2-kg bowling ball sits on top of a building that is 40 meters tall. It falls to the ground. Think about t
he amounts of potential and kinetic energy the bowling ball has:
What is the kinetic energy of the ball as it is half way through the fall?
What is the kinetic energy of the ball as it is half way through the fall?
1 answer:
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The picture in the attached figure
we know that
m ∠ 6=123.5°
m ∠6+m∠2=180°-------> by supplementary angles
so
m∠2=180-m∠6-----> 180-123.5------> m∠2=56.5°
m∠1=m∠2--------> by corresponding angles
so
m∠1=56.5°
the answer is
m∠1 is 56.5°
we know that
m ∠ 6=123.5°
m ∠6+m∠2=180°-------> by supplementary angles
so
m∠2=180-m∠6-----> 180-123.5------> m∠2=56.5°
m∠1=m∠2--------> by corresponding angles
so
m∠1=56.5°
the answer is
m∠1 is 56.5°