The function of the length z in meters of the side parallel to the wall is A(z) = z/2(210 - z)
<h3>How to write a function of the length z in meters of the side parallel to the wall?</h3>
The given parameters are:
Perimeter = 210 meters
Let the length parallel to the wall be represented as z and the width be x
So, the perimeter of the fence is
P = 2x + z
This gives
210 = 2x + z
Make x the subject
x = 1/2(210 - z)
The area of the wall is calculated as
A = xz
So, we have
A = 1/2(210 - z) * z
This gives
A = z/2(210 - z)
Rewrite as
A(z) = z/2(210 - z)
Hence, the function of the length z in meters of the side parallel to the wall is A(z) = z/2(210 - z)
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Answer:
x = 5.4
Step-by-step explanation:
The segment sum theorem tells you ...
AB +BC = AC
36 +(5x -9) = 54
5x = 27 . . . . . . . . . . . subtract 27 from both sides
x = 5.4 . . . . . . . . . . divide by 5
Answer:
w=3
Step-by-step explanation:
3w= 9
divide 3 on both sides
3/3 = 9/3
3/3 cancels out
9/3 = 3
Answer:
D or C more than likely D
Step-by-step explanation: