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mixas84 [53]
4 years ago
7

Which transformations will produce similar, but not congruent, figures?

Mathematics
2 answers:
Ludmilka [50]4 years ago
6 0

Dilations, rotations, and translations produce similar figures.  Reflections don't,
because they produce mirror images, which may be similar in certain cases but
in general are not.

Choices  'B'  and  'C'  are the ones that don't involve reflections.


Finger [1]4 years ago
4 0

Answer:

b                            c

Step-by-step explanation:

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Answer:

\dfrac{(a+b)}{ab}

Step-by-step explanation:

The given expression is :

\dfrac{a}{ab-b^2}+\dfrac{b}{ab-a^2}

It can be solved as follows :

\dfrac{a}{ab-b^2}+\dfrac{b}{ab-a^2}=\dfrac{a}{b(a-b)}+\dfrac{b}{a(b-a)}\\\\=\dfrac{a}{b(a-b)}+\dfrac{b}{-a(-b+a)}\\\\=\dfrac{1}{a-b}(\dfrac{a}{b}-\dfrac{b}{a})\\\\=\dfrac{a^2-b^2}{ab(a-b)}\\\\=\dfrac{(a-b)(a+b)}{ab(a-b)}\\\\=\dfrac{(a+b)}{ab}

So, the solution of the given expression is equal to \dfrac{(a+b)}{ab}.

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3 years ago
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Answer:

<1 = 33 degrees

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Step-by-step explanation:

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tg (A) = \frac {6} {8} = \frac {3} {4}

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