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brilliants [131]
4 years ago
11

I really need help with this and how find the Surface area and Lateral area and what is the length and width for both of the fig

ures. Please help this due by Friday I need to understand the concept of this pleaseeeee help my brain is everywhere.

Mathematics
1 answer:
Ksenya-84 [330]4 years ago
6 0

Answer:

ok fking fk it ill just tell you, the most affordable way is doing it as a 4*3 package, the length will be 16, width 12, and the height 5. the area will be 960in^3, and the SA will be 664 in^2

Step-by-step explanation:

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Answer before I fail this class :)
kifflom [539]

Answer: 15/36

Step-by-step explanation:

You have 36 possible dice outcomes but only 15 of them have a sum of less than 7.

5 0
3 years ago
Evaluate the expression when a= 1/4 and b= 6<br> 5b/32a2=?
Aliun [14]

Answer:

30/64

Step-by-step explanation:

5b=30

32a=8

8^2=64

=30/64

4 0
3 years ago
For what values of b are the vectors \langle -46, b, 10 \rangle and \langle b, b^2, b \rangle orthogonal
Jet001 [13]

Answer:

b = 6 or b = -6 (non-zero vectors)

b = 0 (zero vector)

Step-by-step explanation:

Two vectors \vec{a}=\langle a_1,a_2,a_3\rangle and \vec{b}=\langle b_1,b_2,b_3\rangle are orthogonal if their dot product is equal to 0, or in other words

a_1\cdot b_1+a_2\cdot b_2+a_3\cdot b_3=0

In your case,

\vec{a}=\langle -46, b, 10\rangle\\ \\\vec{b}=\langle b,b^2,b\rangle

Hence, if vectors a and b are orthogonal, then

-46\cdot b+b\cdot b^2+10\cdot b=0\\ \\-46b+b^3+10b=0\\ \\b^3-36b=0\\ \\b(b^2-36)=0\\ \\b(b-6)(b+6)=0\\ \\b=0\text{ or }b=6\text{ or }b=-6

Note, then if b = 0, then \vec{b}=\langle 0,0,0\rangle and zero-vector is orthogonal to any other vectors.

Thus, b = 6 or b = -6.

7 0
3 years ago
Can some one pls help
Doss [256]

Answer:

I will try

Step-by-step explanation:

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Answer:

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5 0
3 years ago
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